Range and y intercept are two characteristics they have in common
Answer:Quadrant II
Step-by-step explanation:
The point is located in the second quadrant because x is negative and y is positive. The quadrants are labeled in counter-clockwise order, starting in the upper-right
The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°
Given m∠P = 40°
We know that : Sum of Angles in a Triangle = 180°
⇒ m∠P + m∠M + m∠O = 180°
⇒ 40° + 90° + m∠O = 180°
⇒ 130° + m∠O = 180°
⇒ m∠O = 180° - 130°
⇒ m∠O = 50°
We can notice that m∠O and m∠1 form a Linear Pair (180°)
⇒ m∠O + m∠1 = 180°
⇒ 50° + m∠1 = 180°
⇒ m∠1 = 180° - 50°
⇒ m∠1 = 130°
Last Option is the Answer
Answer:
slope = 3/5
Step-by-step explanation:
slope = rise/run = 3/5
or (longer way w/ the points)
slope = (y2-y1)/(x2-x1) = (5-2)/(4-(-1)) = 3/5
Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.
angle PQS and TQR are straight angles
angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.
that should bout do it. hope it helped!
