We have been given that a retailer buys cases of 24 shirts for $30/case and then resells them in packs of 5 for $8/pack.
Further, we know that retailer sold all the shirts he purchased and profited $84 on the sale.
Let us first find LCM of 24 and 5. The LCM is 120.
Now, let us assume that the retailer bought 120x shirts. Therefore total profit will be:
We can set this equal to the given profit to figure out the value of x first.
Therefore, the retailer sold 120(2)=240 shirts, that is, 48 packs.
Answer:
Ayush's route is 0.7 km or 700m longer than Sumit route.
Step-by-step explanation:
Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.
We know that,
1 km = 10 hm
1 dam = 0.1 hm
Using these conversions we get
Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm
Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm
Ayush's route is longer.
Difference = 12 hm - 5 hm = 7 hm = 0.7 km [1 km = 10 hm]
Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.
Answer:
4 cups
Step-by-step explanation:
because if you have 2 cups for a half a quart then add another half which means add 2 more cups 2+2=4 cups
Answer:
75th term
Step-by-step explanation:
hope it is well understood
Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
