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LekaFEV [45]
3 years ago
7

Which step did Craig do incorrectly? A Step 1 B C Step 2 Step 3 Step 4 D

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Step 2 was done incorrectly because they did not. flip the positive sign to a negative

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Create a visual plot of the data in the table by constructing a bar graph.
sashaice [31]

The average view of the dress code is that this dress is not good

<h3>Explain how Rashad could collect data to ensure that it is a random sample of the population.</h3>

For Rashad's sample to be a random sample gotten from the population, the following must be considered.

  • First, he must have a defined population. In this case, his population is all the students in his high school (non students are not to be considered)
  • Next, he must have a defined sample size (say 10% or 20% of the total number of students in the school)
  • Next, he must select students at random (a perfect example of this is one of every five or ten students that enters the school gate.
  • Lastly, he must collect data for his sample

<h3>Create a visual plot of the data in the table by constructing a bar graph.</h3>

To do this, we simply create a bar graph.

The response would go into the x-axis, while the number of people would go into the y-axis

See attachment for bar graph

<h3>What is the average view of the dress code? How did you come to this conclusion?</h3>

The average view of the dress code is that this dress is not good

It is considered the average view of the dress code because it is the opinion with the most frequency

<h3>Will the dress change?</h3>

The number of students that do not like the dress as:

210 + 206 + 770 = 1186

Their percentage is

Percentage = 1186/(210 + 206 + 770 + 358)

Percentage = 77%

This means that

Yes, the dress will change

Read more about random sampling at:

brainly.com/question/7301139

#SPJ1

5 0
2 years ago
Can someone help with these problems thanks
timofeeve [1]

Answer:

a. 5 cm

b. 5.2 cm

c. 3.25 in.

d. 2.5 in.

Step-by-step explanation:

Can I pretty please get Brainliest it would help out alot =)

7 0
3 years ago
Graph x+3y&lt;(or equal to)6, indicating the solution set with cross hatching or shading. Explain how you determine where to dra
Sergeu [11.5K]

Step 1

Given;

x+3y\leq6

Required; To graph the inequality

Step 2

Graph the function

\begin{gathered} We\text{ find the y-intercept by setting x=0} \\ 0+3y\leq6 \\ y\leq2 \\ First\text{ point\lparen0,2\rparen} \end{gathered}\begin{gathered} We\text{ find the x-intercept by setting y=0} \\ x+3(0)\leq6 \\ x\leq6 \\ Secon\text{d point;\lparen6,0\rparen} \end{gathered}

So by finding the x-intercept and y-intercept, we can determine where to draw the line. Since the inequality is greater than or equal to the line will be continuous and not broken. Also, we will know the area we will shade by;

\begin{gathered} Resolving\text{ the inequality and make y the subject of the formular} \\ x+3y\leq6 \\ 3y\leq6-x \\ y\leq2-\frac{x}{3} \end{gathered}

Since if we set x=0, we get y < or equal to 2, then we know that the shaded area will be where y is equal to and below. There we will shade below the point (0,2) to represent the solution set.

8 0
1 year ago
A manager at an amusement park wants to know how popular the park's biggest roller coaster is. She counts the number of people w
valkas [14]

Answer: minimum = 0.5

maximum = 9.0

first quartile = 3

median = 5.5

third quartile = 7.5

Step-by-step explanation:

The histogram is shown below and used to obtain the various information

Time (hour) (X)     No of People (F)       FX

0.5                             19                            9.5  -- minimum = 0.5    

1                                20                            20

1.5                              21                             31.5

2                                 22                            44

2.5                              23                            57.5

3                                 24                             72 ----first quartile = 3

3.5                              26                             91

4                                 27                              108

4.5                             28                               126

5                                29                                145

5.5                            30                               165 --median/ inter quartile =5.5

6                               31                                186

6.5                           32                                208

7                               33                                 231

7.5                            34                                255-- third quartile = 7.5

8                               35                                280

8.5                            36                               306        

9                                37                              333 --- maximum = 9

T=85.5                   T = 507                      T=  2666.82     T = TOTAL

mean = sumFX/sumF  =   2666.82/507 = 5.26

Median = middle number = inter quartile =5.5 (507/2 = 253.5 = 254 and  add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29 =269

and 254  close to 269 that is the frequency is within the range and corresponds to 5.5

first quartile = 1/4 *507 = 126.75 = 127 ( add the frequency from top= 19+20+21+ 22+ 23+ 24= 129 and 127 is close to 129)

third quartile = 3/4 * 507 = 380.25 ( add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29+ 30+ 31+32+ 33+ 34 = 399 and 380 is close to 399 so the third quartile is 7.5

minimum is the one with lowest frequency = 0.5 at 19

maximum  or mode is the one with highest frequency = 9 at 37

4 0
3 years ago
The volume of a cone is 31.5 inches cubed and the radius is 3 inches what is the height of the cone
DaniilM [7]
Volume of a cone: (1/3)πr²h

Data:
V=31.5 in³,
r=3 in

Then:
V=(1/3)πr²h
31.5 in³=(1/3)π(3 in)²h
<span>(1/3)π(3 in)²h=31.5 in</span>³
(1/3)π(9 in²)h=31.5 in³
3πin² h=31.5 in³
h=(31.5 in³) / (3π in²)
h≈3.34 in

answer: the height of the cone is 3.34 in. 
3 0
3 years ago
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