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Novay_Z [31]
1 year ago
10

Zero is less than negative fifteen decreased by y, solve for y.

Mathematics
1 answer:
densk [106]1 year ago
4 0

The inequality equation will be 0 < -15 - y. Then the value of the variable y is less than negative 15.

<h3>What is inequality?</h3>

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

Zero is less than negative fifteen decreased by y, can be written as mathematically

0 < -15 - y

Then solving for y, we have

y < -15

The value of the variable y is less than negative 15.

More about the inequality link is given below.

brainly.com/question/19491153

#SPJ1

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zysi [14]

Answer:

1. 52

2. 50

3. 71

4. 28

5. 32

6. 67

8 0
2 years ago
The tank on a petrol lorry is a cylinder 2m in diameter and 7cm long
Nutka1998 [239]

Answer: 0.22 kilolitre

Step-by-step explanation:

First, let’s find the volume of the tank. We know the volume of a cylinder is represented by the equation V=πr^2h,

Radius = 1 m

Height = 7 cm = .07 m

The tank is 0.22 cubic meters

Now that we found the volume, we will try to find how many liters are in the tank.

1 cubic meter = 1 kilolitre

So, 0.22 cu. m = 0.22 kilolitre

5 0
3 years ago
The area of a triangle is 12 square units. The base of the triangle is 4 units. What is the height of the triangle in units?
masya89 [10]

Answer:

6 =h

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh

12 = 1/2 (4) h

12 =2h

Divide each side by 2

12/2 = 2h/2

6 =h

3 0
3 years ago
Which expression is equivalent to the expression shown below?
skelet666 [1.2K]
The answer is -16x-10
5 0
2 years ago
OC bisects AOB, OD bisects AOC, OE bisects AOD, OF bisects AOE, OG bisects BOF. if BOF =120°, find DOE
LiRa [457]

Answer:

∠DOE = 16°

Step-by-step explanation:

The given parameters are;

∠BOF = 120°

∠AOB = 2×∠AOC                        {}      Given

∠AOC = 2×∠AOD                     {}         Given

∠AOD = 2×∠AOE      {}                         Given

∠AOE = 2×∠AOF {}                               Given

Therefore;

∠AOB = 16×∠AOF                 {}              Angle addition postulate

∠BOF = ∠AOB - ∠AOF = 16×∠AOF  - ∠AOF = 15×∠AOF {} Transitive property

15×∠AOF = 120°  

∠AOF = 120°/15 = 8°

Given that OE bisects ∠AOD, we have;

∠AOE ≅ ∠DOE                      {}                    Angles bisected by a line

From;

∠AOE = 2×∠AOF, we have;  {}                               Given

Therefore;

∠AOE = ∠DOE = 2×∠AOF = 2×8° = 16°

∠DOE = 16°.

8 0
3 years ago
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