Ask question

Ask question

All categories

3 years ago

9

Graph the inequality below on the number line.

y > 6" alt=" y > 6" align="absmiddle" class="latex-formula">

1 answer:

gogolik [260]3 years ago

6 0

This is the answer I hope this helps

You might be interested in

Identify the asymptotes and state the end behavior of the function f(x)=5x/x-25

AnnyKZ [126]

Using it's concepts, it is found that for the function $f(x) = \frac{5x}{x - 25}$ :

The vertical asymptote of the function is x = 25.

The horizontal asymptote is y = 5. Hence the end behavior is that $y \rightarrow 5$ when $x \rightarrow \infty$ .

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. They also give the end behavior of a function.

In this problem, the function is:

$f(x) = \frac{5x}{x - 25}$

For the vertical asymptote, it is given by:

x - 25 = 0 -> x = 25.

The horizontal asymptote is given by:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = 5$

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

8 0

2 years ago

Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average

aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let $\mu_{1}-\mu_{2}$ be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes $n_{1} = 40$ and $n_{2} = 35$ , the unbiased point estimate for $\mu_{1}-\mu_{2}$ is $\bar{x}_{1} - \bar{x}_{2}$ , i.e., 699-682 = 17.

The standard error is given by $\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$ , i.e.,

$\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}}$ = 9.8198.

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is $Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}$ and the observed value is $z_{0} = \frac{17}{9.8198} = 1.7312$ . Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for $\mu_{1}-\mu_{2}$ is given by $17\pm (z_{0.05/2})9.8198$ , i.e., $17\pm (z_{0.025})9.8198$ where $z_{0.025}$ is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0

4 years ago

I WILL GIVE BRAINLIEST!!!! Solve the problems. Write the complete proof in your paper homework and for online (only) respond to

Komok [63]

Answer:

Step-by-step explanation:

we need the problems to solve so erm yeah can you like tell me them please but to solve triangles you have to find the angles. hope i helped a bit

7 0

3 years ago

Read 2 more answers

Some one help me !!!!

Sladkaya [172]

Answer: I cant see image!!!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How to do long division with 540÷36

ehidna [41]

divide 36 into 540 36 will divide into the 54 1 time subtract 36 from 54, that gives you 18, bring down the zero from the number 540, now you have 180 to divide by 36, 36 will divide into 180 five times, so your answer is 15

The answer is 15

7 0

3 years ago