Both point (5,12) and (11,12) lie on the horizontal line y=12.
If these two points is a leg of the triangle, the other leg must be perpendicular to the horizontal line, that is, the other leg must be vertical, but passing through either (5,12) or (11,12), i.e. lies on either the vertical line x=5 or x=11.
There is only one point that passes through x=11, i.e. point A(11,4).
Answer:
, n < -16
Step-by-step explanation:
To write this into an inequality you need to recognize keywords. The first keyword is "sum" this means the two numbers must be added; so the first part of the inequality is 4+n. Then, it says the sum is "divided by" 2; this means both numbers must be put over two like 
. Finally, this is "less than" negative. Therefore, this must be an inequality with a sign opening towards -6. So the final answer is .
To solve the inequality isolate the variable. Multiply both sides by 2, so the new inequality is 
. Next, subtract 4 from both sides. The answer is n < -16.
Answer:
x + 4
Step-by-step explanation:
Area of rectangle= length × breadth
In this question, one length is 5x + 3 and the area is 5x^2 + 23x + 12
This means that;
5x2 + 23x + 12 = 5x + 3 (b)
Hence, to get the other length (b) = 5x2 + 23x + 12/ 5x + 3
To get the other length, we can factorize the algebraic expression;
5x2 + 23x + 12
Product: 60x^2 (20x × 3x)
Sum: +23x (20x + 3x)
Hence;
= 5x^2 + 20x + 3x + 12
Next, we find factors;
5x (x+4) + 3 (x+4)
Therefore, the factors are (5x + 3) and (x +4)
This means that the other length is (x +4)
AG≈GB;
Find GB using pythagorean theorem: 4²+3²=c²,
√c=√25=5. AG=5
