Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
I think it’s the third option
Answer:
The rate rate of change of radius is
inches per second when the diameter is 12 inches.
The radius is changing more rapidly when the diameter is 12 inches.
Step-by-step explanation:
Consider the provided information.
A spherical balloon is being inflated at a rate of 3 cubic inches per second.
The volume of sphere is 
Differentiate the above formula with respect to time.

Substitute the respective values in the above formula,


The rate rate of change of radius is
inches per second when the diameter is 12 inches.
When d=16


Thus, the radius is changing more rapidly when the diameter is 12 inches.
Answer:
5 packages of water and 3 packages of cheese sticks
Step-by-step explanation:
the least common multiple of 6 and 10 is 30