The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
Answer:
A:∑j=15(2j−5)
Step-by-step explanation:
a = -3
d = -1 - (-3) = -1 + 3 = 2
j-th term: a + (j-1)d
-3 + (j - 1)(2)
-3 + 2j - 2
2j - 5
Answer:
15
Step-by-step explanation:
var a = 3
then a= 3
var b = 5
then b = 5
a ( a new variable ) = a * b = 3 * 5
Hi,
Your equation is y=-3/8x+3 because if you do rise over run you get a slope of -3/8 and the y intercept is 3.
Hope this helped!
Hello there,
202.366 to the nearest hundredth would be 202.37.
So what I did was I look at the 366 in the problem.
We want to round the to the nearest hundredth.
So what we would do it notice how the 66 in over 50.
The rule is if it's over 50, we round it to the nearest.
So your answer would be 202.37.
Hope this helps.
~Jurgen
