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Licemer1 [7]
1 year ago
8

A Farmer Leans a 12 ft Ladder Against A Barn. The Base of the Ladder Is 6ft From The Barn.l To The Nearest Foot, How High on the

Barn Does The Ladder Reach???
Mathematics
1 answer:
vlada-n [284]1 year ago
5 0

Answer:

10 ft to nearest foot.

Step-by-step explanation:

We use the Pythagoras theorem:

12^2 = 6^2 + h^2    where h is the height on the barn

h^2 = 12^2 - 6^2

h^2 = 144 - 36 = 102

h= √108 = 10.39

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The graph to the right represents Mario's mile time in minutes,y, based
Mashcka [7]

The line slopes downward. More specifically, as x increases, y decreases. Since x is the number of hours trained and y is the mile time, this must mean that the more Mario trains, the shorter his mile time gets.

8 0
2 years ago
How do u solve this?
lara [203]

Answer:

x=5

Step-by-step explanation:

Graph each side of the equation. The solution is the x-value of the point of intersection.

6 0
2 years ago
An electronic device factory is studying the length of life of the electronic components they produced. The manager selects two
Temka [501]

Answer:

The confidence interval will be given by:

200000 \pm 44.72z, in which z is related to the confidence level.

For a confidence level of x%, z is the value in the z-table that has a pvalue of 1 - \frac{1 - z}{2}

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In the context of this problems:

It means that the sampling distributions of the sample mean of 500 components will be approximated normal, with mean 200,000 and standard deviation s = \frac{1000}{\sqrt{500}} = 44.72

To build the confidence interval:

The confidence interval for the average length of life of the electronic components they produced will be given by:

200000 \pm 44.72z, in which z is related to the confidence level.

For a confidence level of x%, z is the value in the z-table that has a pvalue of 1 - \frac{1 - z}{2}

3 0
2 years ago
NEEED HELP ASAP PLEASE
garik1379 [7]

Step-by-step explanation:

( {m}^{15} )( {m}^{3} ) ^ {- 4}  \\  = ( {m}^{15} )( {m}^{3 \times  - 4} )  \\  = ( {m}^{15} )( {m}^{ - 12} ) \\  =  {m}^{15 + ( - 12)}  \\  =  {m}^{15 - 12}  \\  =  {m}^{3}  \\  {m}^{x}  =  {m}^{3}  \\ x = 3

7 0
2 years ago
Convert the given function into a logarithmic function: f(x)=36.77e^(-0.72x)
Likurg_2 [28]
F(x) = 36.77e^(-0.72x)
log f(x) = log36.77e^(-0.72x)
log f(x) = log 36.77 + log e^(-0.72x)
log f(x) = 3.6 + (-0.72x)log e
log f(x) = 3.6 - 0.72x
0.72x = 3.6 - log f(x)
x = 5 - 1.39 log f(x)
7 0
3 years ago
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