B. and D. work. You are trying to figure out how many more cars they painted in the first and second years together than the third year. (5,000+7,213)-8,201=4,012
Answer:
y^2+xy+x+3y+2
Step-by-step explanation:
first of all we have to multiplies the y in the second bracket for all numbers in the first bracket.
so we have:
xy+y^2+2y
now we have to do the same with 1
x+y+2
now we have to unite the two solutions
xy+y^2+2y+x+y+2
at least we have to added up the similar terms (that have the same literal part)
y^2+xy+x+3y+2
Answer:
65
Step-by-step explanation: