Answer:
(-12 , 2)
Step-by-step explanation:
<u>GIVEN :-</u>
- Co-ordinates of one endpoint = (-4 , -10)
- Co-ordinates of the midpoint = (-8 , -4)
<u>TO FIND :-</u>
- Co-ordinates of another endpoint.
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
<em><u>Section Formula :-</u></em>
Let AB be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =
<u>PROCEDURE :-</u>
Let the co-ordinates of another endpoint be (x , y)
So ,
First , lets solve for x.
Now , lets solve for y.
∴ The co-ordinates of another endpoint = (-12 , 2)
Answer:
9
Step-by-step explanation:
List out the factors of the three numbers.
18: 1, 2, 3, 6, 9, 18
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
45: 1, 3, 5, 9, 15, 45
The largest number that all three of these lists share is 9, so 9 is the GCF.
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Answer:
yes, 1 can never equal 2 unless it is manipulated (ex: 1(2) = 2)
because one is not being manipulated to equal 2 here, it is a false statement and will always be a false statement.
Answer:
Maximize C =
and x ≥ 0, y ≥ 0
Plot the lines on graph
So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)
Substitute the points in Maximize C
At (0,1.7)
Maximize C =
Maximize C =
At (2.125,0)
Maximize C =
Maximize C =
At (0,0)
Maximize C =
Maximize C =
So, Maximum value is attained at (2.125,0)
So, the optimal value of x is 2.125
The optimal value of y is 0
The maximum value of the objective function is 19.125
