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Musya8 [376]
3 years ago
10

Write in standard form​

Mathematics
1 answer:
ikadub [295]3 years ago
8 0

Answer:

Step-by-step explanation:

1. 17h + 12

2. 4j +3k -5

3. 6b + 12c -6

4. 22x + 5

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How much interest will $875.00 earn after 3 months at 5.5%?
ZanzabumX [31]

Answer:

I = Prt

Substitute the given information. Remember to write the percent in decimal form. I = (500)(0.06)(3)

Simplify. I = 90

Check your answer. Is $90 a reasonable interest earned on $500 in 3 years? In 3 years the money earned 18%. If we rounded to 20%, the interest would have been 500(0.20) or $100. Yes, $90 is reasonable.

The simple interest is $90.

Step-by-step explanation:

Hope this <u><em>Helped!</em></u> :D

8 0
3 years ago
Suppose that 0.10 of population is colourblind if 25of sample drown from this population find probability that at least 7 have c
Leokris [45]

Answer:

P(X \geq 8)=22*10^{-4}

Step-by-step explanation:

From The Question we are told that

Prob that population is colourblind P(C)=0.10

Sample size N=25

Generally the equation for Number of color blinds is mathematically given by

  P(X \geq 8)=\sum^{25}_{x=8}(25..x)(0.10)^x(0.90)^25-x

  P(X \geq 8)=22*10^{-4}

8 0
3 years ago
Cameron sent a chain letter to his friends, asking them to forward the letter to more friends.
dimaraw [331]

Answer:

Step-by-step explanation:

5 0
3 years ago
Please help and thank you!
bogdanovich [222]

the answer is 13 :))
4 0
3 years ago
Read 2 more answers
What are the roots of the polynomial equation x3 - 6x = 3x2 - 8? Use a graphing calculator and a system of equations.
makkiz [27]

Answer:

d : 4, 1, -2.

Step-by-step explanation:

There's no need for a calculator in my opinion because we can use the rational root theorem which states that the equations of this form:

\sum_{i=0}^{n} a_{i}x^i = 0 = a_{0} + a_{1}x + a_2x^2 + ... + a_nx^n = 0\\ a_i \in \mathbb{Z}

Have rational roots, than the roots are of the form: \frac{k \cdot a_o}{p \cdot a_n}, \ where \ k, p \in \mathbb{Z}.

Rewriting the equation we have:

x^3 - 3x^2 -6x + 8 = 0\\By \ our\ previous \ claim \ x \in D_8 \ where \ D_n \ the \ set \ of \ divisors \ of \ n.\\D_8 = \{\pm 1, \pm 2, \pm 4, \pm 8\} \\We \ plug \ in \ some \ number from \ D_8.\\Letting \ x = -2;\\(-2)^3 -3(-2)^2 -6(-2) + 8 = 0 \ \ \ Thus \ x+2 \ is \ a \ factor.\\We \ can \ now \ simplify \ the \ eq. \ using \ Polynomial \ Long \ Division.

x^3 -3x^2 -6x + 8 = (x+2)(Q(x))\\To \ find \ Q \ we \ divide \ the \ original \ equation \ by \ x + 2; which \ yields:\\Q(x) = x^2 - 5x + 4.\\So \ we \ can \ use \ the \ quadratic \ formula \ to \ find \ the \ roots:\\x = 4,x = 1. \\Thus \ x \in \{-2, 1, 4\}. \ \ These \ are \ all \ the \ roots.

5 0
4 years ago
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