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nataly862011 [7]
2 years ago
8

Suppose that 0.10 of population is colourblind if 25of sample drown from this population find probability that at least 7 have c

oroblind
Mathematics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

P(X \geq 8)=22*10^{-4}

Step-by-step explanation:

From The Question we are told that

Prob that population is colourblind P(C)=0.10

Sample size N=25

Generally the equation for Number of color blinds is mathematically given by

  P(X \geq 8)=\sum^{25}_{x=8}(25..x)(0.10)^x(0.90)^25-x

  P(X \geq 8)=22*10^{-4}

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Use the grouping method to factor this polynomial completely.<br> 3x3 + 12x2 + 2x + 8
dezoksy [38]

Answer:

(3x^2 + 2)(x + 4).

Step-by-step explanation:

3x3 + 12x2 + 2x + 8

3x^2(x + 4) + 2(x + 4)   The  x + 4 is common to the 2 groups so we have:

(3x^2 + 2)(x + 4).

3 0
3 years ago
Please tell me the steps to this problem. i will give brainliest
gayaneshka [121]

Option C: -3 is the average rate of change between x=-1 and x=1

Explanation:

The formula to determine the average rate of change is given by

Average rate of change = \frac{y_2-y_1}{x_2-x_1}

We need to find the average rate of change between x=-1 and x=1

Thus, from the table, we have,

x_1=-1 , y_1=5

x_2=1 , y_2=-1

Thus, substituting these values in the formula, we get,

Average rate of change = \frac{-1-5}{1+1}

                                        =\frac{-6}{2}

                                        =-3

Thus, the average rate of change between x=-1 and x=1 is -3.

Hence, Option C is the correct answer.

6 0
3 years ago
Help?? LOL I’m literally so confused
Gennadij [26K]

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1

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8 0
2 years ago
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the numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it
lorasvet [3.4K]

We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Sample number is, n(S)=11.

We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.

Probability of picking an even number would be :-

P(even numbers) = \frac{6}{11}

Now we replace the card and want to get a 7 in second attempt.

Probability of picking a 7 would be :-

P(number 7) = \frac{1}{11}

Now Probability of this event = P(even numbers) × P(number 7)

Probability = (\frac{6}{11} )(\frac{1}{11} ) = \frac{6}{121}

So final answer is \frac{6}{121}.

3 0
3 years ago
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