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Ede4ka [16]
3 years ago
7

Tough Math Help !

Mathematics
1 answer:
arsen [322]3 years ago
4 0
Put 4 months over 12 months. Reduce to 1/3.

i=prt
i=300(0.9)(1/3)
i=$90
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Find the distance between the point (3, 5) and a line with the equation 5 x - 3 y + 10 = 0
timama [110]

The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.

<h3>What is the distance between a point and a line?</h3>

Let (x₁, y₁) be the point and ax + by + c = 0 be the line.

Then the distance between a point and a line will be

\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}

The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.

Then the distance between them will be

\rm d = \dfrac{|5 *3 - 3 *5 + 10|}{\sqrt{5^2 + (-3)^2}}\\d = \dfrac{10 }{\sqrt{34}} \ units

Learn more about the distance between a point and a line here;

brainly.com/question/11558698

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7 0
2 years ago
Solve 4x - 5 = 19.<br> O A. x = 8<br> O B. x = 10<br> C. x = 6<br> O D. x = 3.5
Basile [38]

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