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Elden [556K]
3 years ago
14

Please help and explain.

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

Domain: All real numbers greater than or equal to 1.

Step-by-step explanation:

Answer 1: -14 is not in the domain

Answer 2: 4 is included in the domain

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Anyone understand this if so plz respond with answer
Archy [21]

Answer:

I dont know the answer

Step-by-step explanation:

But you can find the answer by figuring out what a domain and a range iss and chose which one is a domain and a range you can find what a domain and a range is on google

6 0
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What is the discount and sale price of a $300 item that has been discounted 10%?
Paha777 [63]
270 I think if not my bad
7 0
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Analyze the asymptotes of the function.
koban [17]

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

Step-by-step explanation:

y=\frac{1}{x+1}

To find vertical asymptote we set the denominator =0 and solve for x

x+1=0 (subtract 1 from both sides)

x=-1

So, vertical asymptote at x=-1

To find horizontal asymptote we look at  the degree of both numerator and denominator

there is no variable at the numerator , so degree of numerator =0

degree of denominator =1

When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

5 0
3 years ago
26 is 65% of what number?
Bezzdna [24]

Answer:

40

Step-by-step explanation:

26 is 65% of 40

6 0
2 years ago
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Which expression is equivalent to (sin x + 1)(sin x − 1)? A. cos2x B. -cos2x C. cos2x + 1 D. cos2x − 1 E. -cos2x + 1
Semenov [28]

ANSWER

B.

- \cos^{2} x

EXPLANATION

The given expression is

(sin x + 1)(sin x − 1)

Note that:

(x + 1)(x - 1) =  {x}^{2}  - 1

This implies that,

( \sin \: x + 1)( \sin \: x - 1)  =   \sin^{2} x - 1

We can factor -1 on the right hand side to get,

( \sin \: x + 1)( \sin \: x - 1)  =    - (1 - \sin^{2} x )

Note that from the Pythagorean Identity

1 - \sin^{2} x = \cos^{2} x

We apply this identity to obtain:

( \sin \: x + 1)( \sin \: x - 1)  = - \cos^{2} x

The correct choice is B

4 0
3 years ago
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