<em>x = 3</em>
<em>y = 1</em>
- <em>Step-by-step explanation:</em>
<em>Hi ! </em>
<em>6x - 5y = 13</em>
<em>9y - 15 + 2x = 0</em>
<em />
<em>6x - 5y = 13</em>
<em>2x + 9y = 15 | ×(-3)</em>
<em />
<em>6x - 5y = 13</em>
<em>- 6x - 27y = - 45</em>
<em>add</em>
<em />
<em>6x - 6x - 5y - 27y = 13 - 45</em>
<em>- 32y = - 32 | ×(-)</em>
<em>32y = 32</em>
<em>y = 1</em>
<em>replace y = 1</em>
<em>6x - 5(1) = 13</em>
<em>6x - 5 = 13</em>
<em>6x = 13 + 5</em>
<em>6x = 18</em>
<em>x = 3</em>
<em>Good luck !</em>
<em />
Answer:
The Least Common Multiple (LCM) of 
Step-by-step explanation:
<u>Definition of LCM</u>
The LCM of a, b , c is the smallest multiplier that is divisible by a, b and c
Here the three terms are :


since 
Factoring using prime factorization we get
³
=
(1)
Factoring
we get
(2)
Factoring
we get
(
(3)
The LCM is the multiple of each of the highest power in each factor

Answer: The width of the field = 160 feet
Step-by-step explanation:
We are given that , A field is
yards wide.
That means , The width of the field =
yards
Since , the fraction is in mixed for , so first we convert this into improper fraction.

Therefore , the width of the field =
yards
Since 1 yard = 3 feet.
⇒ the width of the field =
feet
Therefore , the width of the field = 160 feet
Answer:
<h3>The value of

is

</h3><h3>The value of

is

</h3><h3>The partial derivative at s=-5 and t=10 is

is

</h3><h3>The partial derivative at s=-5 and t=10 is

</h3>
Step-by-step explanation:
Given that the Function point are 
,
and s = -5, t = 10
<h3>To find

and

using the appropriate Chain Rule :
</h3>
Substitute the values of x and y in the above equation we get


<h3>Now partially differentiating w with respect to s by using chain rule we have
</h3>



<h3>Therefore the value of

is

</h3>

<h3>Now partially differentiating w with respect to t by using chain rule we have
</h3>


<h3>Therefore the value of

is

</h3>
Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :





<h3>Therefore the partial derivative at s=-5 and t=10 is

is

</h3>






<h3>Therefore the partial derivative at s=-5 and t=10 is

</h3>