Answer:
The statement is true
Step-by-step explanation:
The question is as following :
is divisible by 7 and 19, true or false?
The given expression is
Take 
as a common
So, 
divided 7 = 
And divided 19 = 
is divisible by 7 and 19 (<u>True</u>)
Answer:
B
Step-by-step explanation:
The figure is a trapezium with area (A) calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 8, a = 10 and b = 6, thus
A = × 8 × (10 + 6) = 4 × 16 = 64 cm² → B
Answer:
Cos x = 1 - 
+ 
- 
+ ...
Step-by-step explanation:
We use Taylor series expansion to answer this question.
We have to find the expansion of cos x at x = 0
f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x
Now we evaluate them at x = 0.
f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1
Now, by Taylor series expansion we have
f(x) = f(a) + f'(a)(x-a) + 
+ 
+ 
+ ...
Putting a = 0 and all the values from above in the expansion, we get,
Cos x = 1 - + - + ...
The hot dogs remaining are decreasing by 11 as 2 minutes go by.
11 / 2 = 5.5
So he's eating 5.5 hot dogs per minute.
Minutes 2 4 6 8 9
Hot dogs remaining 49 38 27 16 5
In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.
P=(no. of favourable outcomes)/(no. of possible outcomes)
When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.
1) P(getting 1)=1/6
expected frequency of getting 1
=P(getting)1)×no. of trials
=1/6×600=100
But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.
Therefore, the dice is not fair.
2) P(getting a tail)=0.3
estimate for the number of times the coin will land on a tail
=expected frequency of getting a tail
=P(getting a tail)×no. of trials
=0.3×150=45
3)P(getting a six)=2/3
expected frequency of getting a six
=P(getting a six)×no. of trials
=2/3×300=200
4)P(getting a three)=0.5
expected frequency of getting a three
=P(getting a three)×350
=0.5×350=175
