Question

4. Solve the following system of equations for x.

Answer 1

We are given the system of equations -:

$\large{ \begin{cases} 2x + 3y = - 14 \\ y = 6x + 22 \end{cases}}$

Since the second equation is y-isolated equation. It can be substituted as y = 6x+22 in the first equation.

$\large{2x + 3(6x + 22) = - 14}$

Expand 3 in the expression so we can combine like terms and isolate x-variable.

$\large{2x + 18x + 66 = - 14}$

Then combine like terms.

$\large{20x + 66 = - 14}$

Get rid of 66 from the left side by subtracting both sides by itself.

$\large{20x + 66 - 66 = - 14 - 66} \\ \large{20x = - 80}$

To finally isolate the variable, divide both sides by 20 so we can leave x only on the left side.

$\large{ \frac{20x}{20} = \frac{ - 80}{20} }$

Simplify to the simplest form.

$\large{x = - 4}$

Normally, we have to find the y-value too but since we only find x-value. The answer is x = -4.

Answer

• x = -4

I hope this helps! If you have any questions or doubts regarding my answer, explanation or system of equations, feel free to ask!