(I) 2/3 is a zero of P(x)
(II) 0 is a zero of P(x)
(III) (-d/c) is a zero of P(x)
<u>Step-by-step explanation:</u>
<h3>(I) P(x) = 3x - 2</h3>
Here, P(x) = 3x - 2
To find the zeroes of P(x)
let P(x) = 0
∴ 3x - 2 = 0
∴ 3x = 2
∴ x = 2/3
Thus, 2/3 is a zero of P(x)
<h3>(II) P(x) = 9x</h3>
Here, P(x) = 9x
To find the zeroes of P(x)
let P(x) = 0
∴ 9x = 0
∴ x = 0/9
∴ x = 0
Thus, 0 is a zero of P(x)
<h3>(III) P(x) = cx + d, c ≠ 0</h3>
Here, P(x) = cx + d
To find the zeroes of P(x)
let P(x) = 0
∴ cx + d = 0
∴ cx = -d
∴ x = (-d/c)
Thus, (-d/c) is a zero of P(x)
<u>-TheUnknownScientist</u>
Answer:
x ≥ -2
Step-by-step explanation:
Answer:
Step-by-step explanation:
AC² + AP² = PC²
AC² + 5² = 13²
AC = 12
radius = AC/2 = 6
Answer:
Step-by-step explanation:
Answer:
120 peas in 3 pings
Step-by-step explanation:
(5x8)3