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Diano4ka-milaya [45]
3 years ago
10

What value of n makes this expression equal to 6

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer:

im going to say 3 or 2 because 3x2+6

Step-by-step explanation:

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Someone please solve this​
Wittaler [7]

Step-by-step explanation:

2 x  \times  \frac{1}{4}  - 1 \times  \frac{1}{4}  - 2 \frac{1}{4}  = 1 \times  \frac{1}{4}

\frac{2}{8}  -  \frac{1}{4}  -  \frac{2}{8}  =  \frac{1}{4}

and then minus them

8 0
3 years ago
Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete
bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}

b) 19 inches and 50 inches

\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}

c) 33 centimeters and 80 centimeters

\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}

Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.

6 0
4 years ago
Find the cost of a $19,500 car plus a 6% sales tax
Scrat [10]
There are 2 ways to do this...

19,500(1.06) = 20,670

or

19,500 + 0.06(19,500) = 19,500 + 1170 = 20670
8 0
3 years ago
Help with question 3 please
mel-nik [20]
Score = 6x+y

so 6x+y = xy
⇒ 6x = xy-y
⇒ 6x = y(x-1)
⇒ y = 6x/(x-1)

for x=0, y=0
x=1 , not possible
x=2, y = 12
x = 3, y = 9
x = 4, y = 8
x = 5, y = 7.5 (not possible)
x = 6 , y = 7.1 (not possible)
x = 7, y = 7
x = 8, y = 6.85 (not possible)
x = 9, y = 6.75 (not possible)...

Only five scores are possible.


6 0
4 years ago
\int\limits^0_∞ cos{x} \, dx
JulijaS [17]

Answer:

\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)

General Formulas and Concepts:

<u>Pre-Calculus</u>

  • Unit Circle
  • Trig Graphs

<u>Calculus</u>

  • Limits
  • Limit Rule [Variable Direct Substitution]:                                                     \displaystyle \lim_{x \to c} x = c
  • Integrals
  • Integration Rule [Fundamental Theorem of Calculus 1]:                             \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)
  • Trig Integration
  • Improper Integrals

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^0_\infty {cos(x)} \, dx

<u>Step 2: Integrate</u>

  1. [Improper Integral] Rewrite:                                                                         \displaystyle  \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx
  2. [Integral] Trig Integration:                                                                             \displaystyle  \lim_{a \to \infty} sin(x) \bigg| \limits^0_a
  3. [Integral] Evaluate [Integration Rule - FTC 1]:                                               \displaystyle  \lim_{a \to \infty} sin(0) - sin(a)
  4. Evaluate trig:                                                                                                 \displaystyle  \lim_{a \to \infty} -sin(a)
  5. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  -sin(\infty)

Since we are dealing with infinity of functions, we can do a numerous amount of things:

  • Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).
  • Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.

∴  \displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Improper Integrals

Book: College Calculus 10e

7 0
3 years ago
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