Answer:
The inverse is 1/3 (x+1)
Step-by-step explanation:
y = 3x-1
Exchange x and y
x = 3y-1
Solve for y
Add 1 to each side
x+1 = 3y-1+1
x+1 = 3y
Divide each side by 3
(x+1)/3 = 3y/3
1/3(x+1) =y
The inverse is 1/3 (x+1)
Answer:
i think H(5) plus the 50 $ but it may be wrong
Step-by-step explanation:
If H is 60 then 5 times is 300 plus the 50 he already had so it all adds up to 350
Convert the mixed numbers to improper fractions, then find the LCD and combine.
Exact Form:
7/3
Decimal Form:
2.¯3
Mixed Number Form:
2/1/3
Answer:
2097150
Step-by-step explanation:
<u>GIVEN :-</u>
- First term of G.P. = 6
- Forth term of G.P. = 384
<u>TO FIND :-</u>
- Sum of first 10 terms of the G.P.
<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>
<em>Geometric Progression :-</em>
- It's a sequence in which the successive terms have same ratio.
- General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
- Sum of 'n' terms of a G.P. ⇒
.
<em>[NOTE :- </em>
can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>
<u>SOLUTION :-</u>
Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.
⇒ a = 6
It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-


Divide both the sides by 6.


![=> r = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%3D%3E%20r%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
Sum of first 10 terms 


