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lara31 [8.8K]
3 years ago
14

I’m confused about this question can someone help me please it’s multi step equations

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Step-by-step explanation:

If V doesnt have a value

Furst step we remive the parantheses

-26-6v=-40v-35

We move the terms around for a solvable equation

-6v+40v=-35+26

We add up the terms

34v=-9

now we neee to find V

9

V= - ----

34

Alternative form V=0.2647....

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X+y= 2
bija089 [108]

Answer:

11

Step-by-step explanation:

11

4 0
3 years ago
Read 2 more answers
2. Maria is monitoring the temperature of
stiks02 [169]

Here, we are required to determine after how many minutes will the two substances be at the same temperature.

The equation of when the two substances will be at the same temperature and the solution are as follows;

(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).

(b) The solution is, x = 3.285minutes.

For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;

  • T(a) = 96.2 + 1.5(x)

For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;

  • T(b) = 98.5 + 0.8(x)

(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).

  • T(a) = T(b)

The equation is therefore;.

96.2 + 1.5(x) = 98.5 + 0.8(x)

(b) To determine the solution;

1.5x - 0.8x = 98.5 - 96.2

0.7x = 2.3

x = 2.3/0.7

x = 3.285minutes.

Read more:

brainly.com/question/20248109

5 0
2 years ago
What is the area of the model in the problem?
nata0808 [166]

Answer:

A=x^2+12x+27\ units^2

Step-by-step explanation:

we know that

The area of the model is equal to the area of a rectangle

The area of a rectangle is equal to

A=LW

we have

L=x+9\ units

W=x+3\ units

substitute

A=(x+9)(x+3)

Apply distributive property

A=x^2+3x+9x+27

Combine like terms

A=x^2+12x+27\ units^2

4 0
4 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
Help!! I hate geometryyyy
miskamm [114]

Answer:

AFB, BDC, and FBD

Step-by-step explanation:


3 0
4 years ago
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