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Andre45 [30]
3 years ago
11

Which ordered pairs (x,y) are solutions to the linear equation 2x+3y=6

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Answer:

I think it is 0,2

Step-by-step explanation:

Because you need to substitute the ordered pairs into the linear equation:

so,

2(0)+3(2) = 6

             6=6

The two side, so equation are identical, so the correct answer is (0,2).

I hope this helps!

Debora [2.8K]3 years ago
4 0

Answer:

I think it is 0\2

Step-by-step explanation:

Because you need subtitute the orderd pairs into the linear eqaution

so

2(0)+3(2)

6=6

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The sum of two consecutive integers is 65. what are the two integers? show steps please.
Gnoma [55]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

\longmapsto\sf{2x=64}

Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

7 0
2 years ago
Need help asap plzzzz both answers if u can
Tcecarenko [31]

Answer:

where is the question

Step-by-step explanation:

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