Answer:
10 cm
Step-by-step explanation:
From the diagram,
Applying,
lw = 5/2(bh)..................... Equation 1
Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.
make w the subject of the equation
w = 5(bh)/2l............... Equation 2
From the diagram,
Given: l = 12 cm, b = 6 cm, h = 8 cm
Substitute into equation 2
w = 5(6×8)/(2×12)
w = 10 cm
Hence the width of the rectangle is 10 cm
Answer:
14
Step-by-step explanation:
hi! so the question is asking what h is when you input -18 for x, right?
inputing in this question means to substitute, meaning that in this equation, -18 will take the place of x!
- let's see what the equation looks like now
- easy as that!
now let's do the math :)
- because of PEMDAS, remember to do the fraction (dividing) first!
we can change that to --> h = 17 - 3
h = 14
let me know if you're still confused!
Answer:
- 6 bunches of bananas
- 7 pounds of apples
Step-by-step explanation:
We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.
Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...
6B +8(13 -B) = 92
-2B + 104 = 92 . . . . . eliminate parentheses
B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B
13-B = 7 . . . . . . . . . . . the number of pounds of apples
The customer bought 6 bunches of bananas and 7 pounds of apples.
_____
<em>Comment on the solution</em>
You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.
0, 3
- 10, 15
= -10, -12
therefore, the slope is 6/5, and the intercept (c) is as supplied, 3.
the equation, y=mx+c or y = a + bx, can be applied here where m or b = 6/5, and a or c = 3.
therefore the equation is y=6/5x+3.
To test this, you can put in y = 10(6/5)+3, which spits out y = 15. This way we know it *should* work.
is strictly increasing on [0, 5], so
and
so the integral is bounded between
