Answer:
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Step-by-step explanation:
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OK. These problems are easy if you know the quadratic formula,
and they're impossible if you don't.
Here's the quadratic formula:
When the equation is in the form of Ax² + Bx + C = 0
then x = [ -B plus or minus √(B²-4AC) ] / 2A
I'm sure that formula is in your text or your study notes,
right before these questions. You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
you have it memorized and can rattle it off.
The first question says 3x² + 5x + 2 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes ! A=3 B=5 C=2
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
= [ -5 plus or minus √(5² - 4·3·2) ] / 2·3
= [ -5 plus or minus √(25 - 24) ] / 6
= [ -5 plus or minus √1 ] / 6
x = -4 / 6 = -2/3
and
x = -6 / 6 = -1 .
_______________________________________
The second question says
4x² + 5x - 1 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes it is ! A=4 B=5 C= -1
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
Now, you take it from here.
Answer:
4
Step-by-step explanation:
9514 1404 393
Answer:
{Segments, Geometric mean}
{PS and QS, RS}
{PS and PQ, PR}
{PQ and QS, QR}
Step-by-step explanation:
The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.
short leg : long leg = SP/RS = RS/SQ ⇒ RS² = SP·SQ
short leg : hypotenuse = RP/PQ = PS/RP ⇒ RP² = PS·PQ
long leg : hypotenuse = RQ/QP = QS/RQ ⇒ RQ² = QS·QP
I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.
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segments PS and QS, gm RS
segments PS and PQ, gm PR
segments PQ and QS, gm QR
A circle has a radius of 3 An arc in this circle has a central angle of 20 what is the length of the arc
