1. c (multiply by 3 to get 9x - 3y = 15)
2. c (add the new top expression with the bottom one to get 11x = 0) substitute 0 into either equation to get -5)
hope this helps!
(-7,-12) s it both down and to the right of the origin
- 9 and - 3
consider 3 units to the left and right of - 6
- 6 - 3 = - 9 ( 3 units to the left of - 6 )
- 6 + 3 = - 3 ( 3 units to the right of - 6 )
The whole ends up being 42 ft².
Area of a triangle = 1/2 * base * height.
So that lil triangle piece is 1/2 * 2 * 3 = 1/2 * 6 = 3
Now we do the rectangle piece. Area of a rectangle = length * width
So that rectangle is 3 * 7 = 21
If you take away those two, you are left with a trapezoid.
Area of a trapezoid is 1/2 * (base 1 + base 2) * height
Base 1 is the width of the rectangle which is 3. Base 2 is the 6. The height is the given 11 feet minus the 7 feet from the length of the rectangle which is 4.
Plug all this in to the formula you get 1/2 * (6 + 3) * 4 = 1/2 * 9 * 4 = 1/2 * 36 = 18.
Now add all of your areas together;
21 + 3 + 18 = 24 + 18 = 42
Answer:
A)
y^2-6y = 0
or, y(y-6) = 0
or, y = 0 or y = 6
B)
n^2+5n+7 = 7
or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)
or, n^2+5n = 0
or, n(n+5) = 0
or, n=0 or n= -5
C)
2t^2-14t+3 = 3
or, 2t^2-14t = 0
or, 2t(t-7) = 0
or, t=0 or t=7
D)
1/3x^2+3x-4 = -4
or, 1/3x^2+3x = 0
or, 1/3x(x+9) = 0
or, x=0 or x= -9
E)
Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.
THANK YOU FOR READING.
