Decimal (i think but i’m not 100% sure)
Answer:
It is not possible.
Explanation:
In this example, we need to accommodate 473 computers for six clients that are 473 IP addresses.
For this request just we have /22 IPv4 address blocks, this mean
22 red bits 11111111111111111111110000000000 <--- 10 host bits
We must increase red bits to 25, we need these 3 bits to create 6 sub red, in this case, 2^3 = 8 sub red.
Why did we ask 3 bits? Because if we ask only 2, 2^2 = 4, and we need 6 sub red.
25 red bits 11111111111111111111111110000000 7 host bits
In this case, we need more than 260 computers, but just we have 7 bits, this means.
2^7 = 128 and just one customer needs 260, for that is impossible.
Evaluation-the making of a judgment about the amount, number, or value of something; assessment
Domain Name-Is a websites name (ex-Google)
Authoritativeness-The quality of possessing authority. The quality of trustworthiness and reliability.
Accuracy-the quality or state of being correct or precise
Timeliness-the fact or quality of being done or occurring at a favorable or useful time.
Objectivity-the quality of being objective.
Writing Style and Mechanics-Style has to do with how a piece of writing sounds. Everyone has a style which develops along with their writing.
Paragraph structure: Each paragraph should begin with a topic sentence that provides an overall understanding of the paragraph. ...
Sentence length: Sentences should be kept as short as possible so that their structure is simple and readable.
Graphics-are visual images or designs
Links- is an open source text and graphic web browser with a pull-down menu system.
<u>Explanation:</u>
Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:
// C++ program to count even digits in a given number .
#include <iostream>
using namespace std;
// Function to count digits
int countEven(int n)
{
int even_count = 0;
while (n > 0)
{
int rem = n % 10;
if (rem % 2 == 0)
even_count++;
n = n / 10;
}
cout << "Even count : "
<< even_count;
if (even_count % 2 == 0 )
return 1;
else
return 0;
}
// Driver Code
int main()
{
int n;
std::cin >>n;
int t = countEven(n);
return 0;
}
