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3 years ago

HELPPPPPPP I'LL GIVE BRAINLY 3x + 5 ≤ -13

Mathematics

2 answers:

Hitman42 [59]3 years ago

8 0

Answer:

x <-6

Step-by-step explanation:

romanna [79]3 years ago

5 0

Answer:

Step-by-step explanation:

3x + 5 ≤ -13

-5 -5

-18

3x ≤ -18

3x divide by 3. Then divide the other side by three

x ≤ -6

im not 100% sure but thats how I would do it.

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PLS HELP ASAP Cassandra earns $12. 98 an hour working at Key Food. How much money will she earn this month, if she works 36. 7 h

lord [1]

Answer:

476.37

Step-by-step explanation:

$12.98/hr at KF (Key Food)
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2 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit

kondor19780726 [428]

Answer:

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

Step-by-step explanation:

The expression to simplify in this problem is

$7\sqrt[4]{80pq^2r^8}$

Which can be rewritten as

$7(80pq^2r^8)^{\frac{1}{4}}$

Or also as

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}$

Now we can apply the following rule for the calculation of the power of a power:

$(a^m)^n = a^{m\cdot n}$

So we get:

$7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

Which can therefore be rewritten as

$7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

And so, we get

$7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}$

which can be finally rewritten as

$14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}$

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3 years ago