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Arturiano [62]
3 years ago
5

78 x 42 in area model and standard algorithm

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0
3276.................
DanielleElmas [232]3 years ago
3 0
I got 3276. . . . . . . . .
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What is the value of n
Hunter-Best [27]

Answer:

B) n = 6

Step-by-step explanation:

4n + 12 = 8n - 12

Combine like terms

24 = 4n

n = 6

5 0
3 years ago
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Two owners of a cattle ranch, Robert and Val, want to find the average weight for the ranch’s 200 cows. Instead of weighing all
Ivahew [28]

Using it's formula, it is found that Val's margin of error is of 9.8 pounds.

<h3>Margin of error:</h3>

The margin of error is given by the following equation:

M = 1.96\frac{s}{\sqrt{n}}

In which:

  • s is the standard deviation.
  • n is the sample size.

In this problem:

  • The standard deviation is of 50, hence s = 50.
  • Val weighed 100 cows, hence n = 100.

Then:

M = 1.96\frac{s}{\sqrt{n}}

M = 1.96\frac{50}{\sqrt{100}}

M = 9.8

Val's margin of error is of 9.8 pounds.

You can learn more about margin of error at brainly.com/question/14510808

4 0
3 years ago
Determine the surface area of the shape below.
aev [14]

Try this option:

1. the required surface area consists of: A=A₁+A₂+A₃, where

2. A₁=pi*r*l - the surface of the cone:

pi=3.14; r=4/2=2 cm; l=sqrt(6²+2²)=2√10≈6.33 (cm);

A₁=3.14*2*6.33=39.74 (cm²).

3. A₂=a²-pi*r² - the surface of the top plane:

A₂=36-3.14*4=23.43 (cm²).

4. A₃=5*a² - the surface of the five planes of the given cube:

A₃=5*6²=180 (cm²).

5. the required area:

A=39.74+23.43+180=243.17 (cm²).

<u />

<u>Answer: 243.17</u>

5 0
3 years ago
1. While solutions to the general quintic equation in terms of radicals are impossible to obtain, they do exist. Prove that the
Marta_Voda [28]

Answer:

Step-by-step explanation:

Given is a function as x^5-3x+1

Equating to 0 we have equation

If the function f(x) has x intercepts then the solutions are real

Let us use remainder theorem and change of signs rule

f(0) = 1>0

f(-1) = -1+3+1=3

f(-2) = -32+6+1<0

This implies there is a real root between -1 and -2.

f(1) = -1

Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.

f(2) = 32-6+1>0

Since f(1) and f(2) have different signs there exists a real root between 1 and 2.

Thus there are definitely three real solutions as

one between -1 and 0, one between 0 and 1, and third between 1 and 2.

3 0
4 years ago
Read 2 more answers
Find the 11th term of this sequence. -10,20,-40,80...
Morgarella [4.7K]
The difference is not constant therefore there cannot be an 11th term that is correct.

6 0
4 years ago
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