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3 years ago

First to answer gets brainliest

Mathematics

1 answer:

____ [38]3 years ago

8 0

Answer:

a. Imaginary

b. Real (x = 2 + √11, 2 − √11)

c. Imaginary

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The ratio of incorrect to correct answers on Marco's math test was 4 to 6. If Marco missed 39 problems, how many did he get corr

lesantik [10]

39/6= 6.5 then u multiply
6.5 times 4 = 26
which 26 is your answer

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4 years ago

Here brainliest look arE the picture

satela [25.4K]

Answer:

12p = 48

3rd option

Step-by-step explanation:

total photos =48

pages on website = 12

photos on each page = p

then,

p =48/12

that is

12p =48

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3 years ago

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LiRa [457]

Answer:

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Step-by-step explanation:

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3 years ago

Can you help me with that

dezoksy [38]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0

3 years ago