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3 years ago

Help me plssssssssss

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

3 0

Pretty sure it’s d(all of the above)

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What should be subtracted from the product of<br>3/7 and 2/5 to get -4/35?

bonufazy [111]

$\implies {\pink {\boxed {\boxed {\purple {\sf { \: x = \frac{2}{7}}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

Let $x$ be the unknown number.

As per the question, we have

$\: ( \frac{3}{7} \times \frac{2}{5} ) - x = \frac{ - 4}{35}$

➺ $\: \frac{6}{35} - x = \frac{ - 4}{35}$

➺ $\: - x = \frac{ - 4}{35} - \frac{6}{35}$

➺ $\: - x = \frac{ - 4 - 6}{35}$

➺ $\: - x = \frac{ - 10}{35}$

➺ $\: x = \frac{2}{7}$

Therefore, $\frac{2}{7}$ should be subtracted from the product of $\frac{3}{7}$ and $\frac{2}{5}$ to get $\frac{ - 4}{35}$ .

$\large\mathfrak{{\pmb{\underline{\orange{To\:verify}}{\orange{:}}}}}$

$\: ( \frac{3}{7} \times \frac{2}{5} ) - x = \frac{ - 4}{35}$

➼ $\: ( \frac{6}{35} ) - \frac{2}{7} = \frac{ - 4}{35}$

➼ $\: \frac{6}{35} - \frac{2 \times 5}{7 \times 5} = \frac{ - 4}{35}$

➼ $\: \frac{6 - 10}{35} = \frac{ - 4}{35}$

➼ $\: \frac{ - 4}{35} = \frac{ - 4}{35}$

➼ $\: L.H.S.=R. H. S$

$\sf\purple{Hence\:verified. }$

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{☂}}}}}$

3 0

3 years ago

Part D

never [62]

Answer:

Step-by-step explanation:

$y(t>1) = x(t) + y(t-1)\\x(t>1) = 1.2x(t-1)\\y(1) = x(1) = 100\\\\y(t>1) = 1.2x(t-1) + y(t-1)\\y(2) = 1.2x(1) + y(1) = 120+100 = 220\\y(3) = 1.2x(2) + y(2) = 144+220 = 364\\y(4) = 1.2x(3) = y(3) = 172.8+364=536.8\\$

6 0

3 years ago

Help! I’ll mark you brainly and give extra points!!

bezimeni [28]

Answer: 4. No, the graph is NOT a function because using the vertical line test, it intersects at two points at a time.

5. Yes, it is a relation, and it is also a function because once those points are plotted if given the vertical line test, there would not be two points crossed at once. So, yes, it is a function.

6. Yes, it is a relation. No, it does NOT make up a function because a vertical line would intersect all the points given.

4 0

3 years ago

Y=-3x+2<br> Y=2x-3<br> How to solve these equations using substitution or elimination.

Finger [1]

Substitution:
$y=-3x+2 \\
y=2x-3 \\ \\
\hbox{substitute -3x+2 for y in the 2nd equation and solve for x:} \\
-3x+2=2x-3 \\
-3x-2x=-3-2 \\
-5x=-5 \\
x=1 \\ \\
\hbox{substitue 1 for x in one of the equations and solve for y:} \\
y=2 \times 1-3 \\
y=2-3 \\
y=-1 \\ \\
(x,y)=(1,-1)$

Elimination:
$y=-3x+2 \ \ \ |\times (-1) \\
y=2x-3 \\ \\
-y=3x-2 \\
\underline{y=2x-3} \\
y-y=3x+2x-2-3 \\
0=5x-5 \\
5=5x \\
x=1 \\ \\
y=2 \times 1-3=2-3=-1 \\ \\
(x,y)=(1,-1)$

4 0

4 years ago

Read 2 more answers

Which is the first step in solving<br> X-2 = 2?

Vanyuwa [196]

Answer:

The first step is to find a number that when subtracted from 2 gives you 2.

Step-by-step explanation:

The algebraic part of this problem would be to add the -2 (adding 2 to both sides) to both sides, so

first x-2=2, then x-2(+2)=2(+2) which would give us,

x=4

*note: the parenthesis are just to show that we are adding the 2, to make it more understandable.

8 0

4 years ago