We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
First we define variables:
x = distance traveled by player A
y = distance traveled by player B
We have the following system of equations:
x + y = 1550
x = 9y
Solving the system we have:
x = 1395
y = 155
Answer:
x = 1395 yards (player A)
y = 155 yards (player B)
Step-by-step explanation:
2 = 3 - q
1 = (3 - q)×1/2
9 =(3 - q) ×1/2×9
9 = 27 - Q/2
C because it is a rhombis
Answer:
18+2x>_0
18/2 + 2x/2
x= 9
Step-by-step explanation:
first take the 2x to the other side which will automatically change from - to + and then divide both 18 and 2x by 2
