3 years ago

What is the actual slope of a line with the points (-4, 9) and (3, -5)?

Mathematics

2 answers:

Vikentia [17]3 years ago

6 0

Answer:

slope=∆y/∆x=9+5/-4-3=14/-7=-2

goldenfox [79]3 years ago

4 0

Answer:

-2

Step-by-step explanation:

slope equation: (y2-y1)/(x2-x1)

lets use (-4, 9) as x1 and y1 and (3, -5) as x2 and y2

when plugged into the equation we get (9+5)/(-4-3) which ultimately equals -2.

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What’s 3x+6y=12 in the form y=mx+b

zhenek [66]

Hey there!

3x+6y=12

Divide both sides by 3 and your equation would now look like:
x+2y= 4
Move the x to the other side
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Seprate the y by dividing both sides by 2
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