Answer:
(1)
Step-by-step explanation:
Data given and notation
n=100 represent the random sample taken
estimated proportion with the survey
is the value that we want to test
represent the significance level
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.41.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion
is significantly different from a hypothesized value
.
Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Answer:
x(x+1)²
Step-by-step explanation:
x is a common factor to all terms so the first step is to factor it out:
... x(x² +2x +1)
The quadratic factor is recognizable as the square (x+1)², so the factoring is ...
... x(x +1)²
The least amout of parts it can be divided into is 15. (Common denom. Of fractions)
Answer:
hope this help good luck
Step-by-step explanation:
a. H0: μ = 26.6
b. Ha: μ > 26.6
c. Let x = the mean age for online students at De Anza College.
d. Student’s t-distribution
e. 9.98
f. p-value = 0.0000
g. Check student’s solution.
h. i. Alpha: 0.01
ii. Decision: Reject the null hypothesis.
iii. Reason for decision: The p-value is less than 0.01.
iv. There is sufficient evidence to conclude that the mean age of online students at De Anza College is greater than 26.6 years.i. (28.8, 30.0)
X-6x=56
-5x=56/:(-5)
x=-56/5
x=-11 1/5