A figure is located entirely in the third quadrant. If you reflect it over y = 0. Which quadrant will the resulting figure lie i
n?
1 answer:
Answer: Quadrant 2
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Explanation:
Check out the diagram below. An example point in the third quadrant is (-2,-5). This quadrant is the southwest quadrant. Reflect the example point over the x axis (aka the line y = 0) and we get (-2,5). This is shown when we go from point A to point B in the diagram.
The reflection rule is showing that only the y coordinate changes from y to -y. If y is negative, then flip to positive, or vice versa. The x coordinate stays the same.
The point started in quadrant 3 and it moves to quadrant 2 after the reflection over the line y = 0.
Side note: all points on the line y = 0 have a y coordinate of 0
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Answer:
84.5 m
Step-by-step explanation:
It is often helpful to draw a diagram for word problems involving geometric relationships. One for this problem is shown below.
The mnemonic SOH CAH TOA reminds you of the relationship between sides of a right triangle:
Tan = Opposite/Adjacent
Here we're given angles of depression measured from the horizontal (as shown in the diagram), but it is more convenient to use angles measured from the vertical. In particular, ∠BAO is the complement of 60°, and its tangent is the ratio OB/OA:
tan(30°) = OB/OA
OB = (200 m)·tan(30°) ≈ 115.47 m . . . . . . multiply by OA, use OA=200 m
Likewise, we have ...
OC = (200 m)·tan(45°) = 200 m
Then the width of the river is the difference between these values:
BC = OC -OB = 200 m - 115.47 m = 84.53 m
