In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
Step-by-step explanation:
3 cookies= 240 cal
∴ 1 cookie= 240÷3 cal
∴ 5 cookies= (240÷3) × 5
⇒ 240÷3= 80
⇒ 80 × 5= 400
[ans] 400 cal
five to the second power is 5x5 which is 25.
two to the fifth power is 2x2x2x2x2 which is 32.
Arranging in ascending order we have
52 55 59 60 62 65 65 66
The median = (60+62)/2 = 61
The mean = 484 / 8 = 60.5
range = 66-52 = 14
interquartile range = 65 - 57 = 8
pairs = 65
the first six terms of the sequence 
now on this new edited version
so, as you can see, the "common difference" of this arithmetic sequence is d = 5, hmmm what term is 67 anyway?
