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kolezko [41]
3 years ago
9

Please help me..make it right..

Mathematics
2 answers:
mario62 [17]3 years ago
5 0

Answer:

12/18,13/18,14/18,15/18

the next would be 16/18=8/9

Step-by-step explanation:

mr_godi [17]3 years ago
4 0

Answer: 8/9

Step-by-step explanation:

The common multiple they all share is 18, so change the denominator to that for all the fractions.

2/3 = 12/18

13/18 = 13/18

7/9 = 14/18

5/6 = 15/18

The next answer would be 16/18 which is equivalent to 8/9

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2 years ago
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7 0
3 years ago
Read 2 more answers
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
0.25r-0.125+.5r=0.5r show work please want to check mine
Vesna [10]
0.25r-0.125+0.5r=0.5r 0.75r-0.125=0.5r -0.125= -0.25r r=0.5
4 0
3 years ago
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