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3 years ago

Six words have 2 vowels and 2 consonants .How many letters are there in 6 words?How many vowels consonants

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

Answer:

24, 12, 12

Step-by-step explanation:

I do not understand the question, but I believe you gave us how many vowels and consonants are in a word. Then you asked us for how many of them were in 6 words, which is simple math of 4 times 6. I don't get the last part, but I think you asked how many consonants in 6 words, and how many vowels in six words, another simple math question, 2 times 6.

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Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

bearhunter [10]

Answer:

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

6 0

3 years ago

The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de

inna [77]

Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let x₁ = 4

$Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65$

Let x₂ = 7

$Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85$

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

= P(Z≤0.85) - P(Z≤-0.65)

= 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

= 0.5 + A( 0.85) - 0.5 +A(0.65) ( ∵A(-0.65) = A(0.65)

= A(0.85) + A(0.65)

= 0.3023 + 0.2422

= 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

6 0

4 years ago

What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34 Round yo

Galina-37 [17]

We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.

The probability of a data score between two z-scores is given by formula $P(a$ .

Using above formula, we will get:

$P(-1.32$

Now we will use normal distribution table to find probability corresponding to both z-scores as:

$P(-1.32$

Now we will convert $0.27351$ into percentage as:

$0.27351\times 100\%=27.351\%$

Upon rounding to nearest tenth of percent, we will get:

$27.351\%\approx 27.4\%$

Therefore, our required probability is 27.4% and option C is the correct choice.

5 0

3 years ago

Please help!! Will give brainliest

Angelina_Jolie [31]

Answer:

b) 16 rt 2

Step-by-step explanation:

using the 45-45-90 triangle trick,

let x=16

then BC is x rt 2, or 16 rt 2

4 0

3 years ago

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sveta [45]

I think the answer is B.
Hope this helps.

4 0

3 years ago

Read 2 more answers