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alexira [117]
3 years ago
7

Which table represents a linear function?

Mathematics
1 answer:
Digiron [165]3 years ago
5 0
It would be the first one because it’s going up by a constant rate
You might be interested in
Please Help! Show all the steps!
likoan [24]

You can start by subtracting different equations from each other.

3x + 2y + 3z = 1

subtract

3x + 2y + z = 7

2z = -6

divide by 2

z = -3

add the following two expressions together:

3x + 2y + z = 7

3x + 2y + 3z =1

6x + 4y + 4z = 8

subtract the following two expressions:

6x + 4y + 4z = 8

5x + 5y + 4z = 3

x - y = 5

^multiply the whole equation above by 3

3x - 3y = 15

subtract the following two expressions:

3x - 3y = 15

3x + 2y = 10

-5y = 5

divide each side by -5

y=-1

take the following expression from earlier:

x - y = 5

substitute y value into above equation

x - - 1 = 5

2 negatives make a positive

x + 1 = 5

subtract 1 from each side

x = 4

Therefore x = 4, y = -1, z = -3

I checked these with all 3 equations and they worked :)

(it's quite complicated, comment if you don't understand anything) :)

7 0
3 years ago
In an axiomatic system, which category do points, lines, and planes belong to?
scZoUnD [109]
Undefined terms is the category its belongs to.
3 0
3 years ago
Help me with this 1,2,3. For each sequence, Determine with whether it appears to be arithmetic If it does find a common differen
pshichka [43]

Problem 1

<h3>Answer: Arithmetic, common difference = -4</h3>

-------------------

Explanation:

Pick any term of the sequence, and subtract off the previous term to find that,

  • term2 - term1 = -12 - (-8) = -12 + 8 = -4
  • term3 - term2 = -16 - (-12) = -16 + 12 = -4
  • term4 - term3 = -20 - (-16) = -20 + 16 = -4

Each time we get the same result, so that means we have an arithmetic sequence with common difference -4

This indicates that adding -4 to each term, or subtracting 4 from each term, will generate the next one.

Eg: term2 = term1 - 4 = -8-4 = -12.

==========================================================

Problem 2

<h3>Answer: Arithmetic, common difference = 5</h3>

-------------------

Explanation:

Similar to problem 1, this sequence is also arithmetic because we add on 5 to each term to get the next one

  • -6+5 = -1
  • -1+5 = 4
  • 4+5 = 9

Or you could subtract adjacent terms as done in problem 1, to find that the common difference is 5.

==========================================================

Problem 3

<h3>Answer: Not arithmetic</h3>

-------------------

Explanation:

Unlike the previous two problems, this sequence is not arithmetic.

We can see that

  • term2 - term1 = 12 - 3 = 9
  • term3 - term2 = 48 - 12 = 36

The gaps of 9 and 36 aren't the same. We need the same common difference between any adjacent terms to have an arithmetic sequence.

This sequence is instead geometric because

  • term2/term1 = 12/3 = 4
  • term3/term2 = 48/12 = 4
  • term4/term3 = 192/48 = 4

Each quotient is 4, showing the common ratio is 4. To find the next term, we multiply the current term by 4. So the next term after 192 would be 4*192 = 768, then 4*768 = 3072 is next, and so on.

3 0
3 years ago
Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
Area is 96 length is 4x+8 width is x find x
dimulka [17.4K]

Answer

Step-by-step explanation:

The area would be length times width. x(4x+8) =96

4x^2+8x = 96

4x^2+8x-96=0. We need to factor.

It would be factored to (4x-16)(x+6) = 0

x would be -6 (x+6=0)

or x would be 4 (4x-16=0)

Why would the width be negative?!? So the answer is 4

4 0
2 years ago
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