Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.
Answer:
The scatter plot is attached.
Step-by-step explanation:
In a scatter plot, we graph the independent variable on the x-axis and the dependent variable on the y-axis.
In this case, age is independent and weight is dependent.
This means the points we plot are:
(7, 50); (7, 60); (8, 65); (8, 70); (9, 70); (9, 80); (10, 75); and (10, 90).
The answer to your question would be 25 sq ft
Assuming that the figures given are square such that the scale factor between them is equal to 28/8 which can be further simplified into 7/2. The ratio of the perimeter is also equal to this value, 7/2. However, the ratio of the areas is equal to the square of this value giving us an answer of 49/4.
Answer:
(2,-1)
y= -1
x= 2
Step-by-step explanation:
y= -2x+3
4x-3y=11
substitute the value of y into an equation
4x-3(-2x+3)=11
distribute by multiplying numbers in parenthesis by -3
4x+6x-9=11
add 4x to 6x
10x-9=11
add 9 from both sides
10x=20
divide both sides by 10
x=2
substitute the value of x into an equation
y= -2•2+3
multiply -2 to 2
y= -4+3
add -4 to 3 but 4 is negative, so subtract
y= -1
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(2,-1)
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