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2 years ago

Please help me with my work

Mathematics

1 answer:

Thepotemich [5.8K]2 years ago

6 0

Answer:

JM = 5 mm

Step-by-step explanation:

Δ JMK is the right angled triangle ⇒ JM² = JK² + KM²

JM² = 3² + 4²

JM = 5 mm

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o-na [289]

Answer:

1 + 1 = 5 i totally graduated kindergarten.

Step-by-step explanation:

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3 years ago

How many solutions does x2 - 10x=-25 have?

Elina [12.6K]

Answer:

4.2 Solving x2-10x+25 = 0 by Completing The Square . This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.

Step-by-step explanation:

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3 years ago

(2y + 50)" (7x - 248) (5y - 17) (x +44)° Find the value of x and y.

Sveta_85 [38]

Answer:

x = 48

y = 21

Step-by-step explanation:

To find the value of x and y, using the definition of supplementary angles, create an equation to find x and y as follows:

Finding y:-

$(2y + 50) + (5y - 17) = 180$ (supplementary angles definition)

Solve for y

$2y + 50 + 5y - 17 = 180$

Collect like terms

$2y + 5y + 50 - 17 = 180$

$7y + 33 = 180$

$7y + 33 - 33 = 180 - 33$

$7y = 147$

$\frac{7y}{7} = \frac{147}{7}$

$y = 21$

Finding x:-

$(7x - 248) + (x + 44) = 180$ (supplementary angles definition)

Solve for x

$7x - 248 + x + 44 = 180$

Combine like terms

$8x - 204 = 180$

$8x - 204 + 204 = 180 + 204$

$8x = 384$

$\frac{8x}{8} = \frac{384}{8}$

$x = 48$

7 0

3 years ago

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de

OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean $\mu$ = 186 × 17 = 3162

Standard deviation = $29* \sqrt{17}$

Standard deviation = 119.57

$P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})$

$P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})$

$P(X>3417) = P(Z>\dfrac{255}{119.57})$

$P(X>3417) = P(Z>2.133)$

$P(X>3417) =1- 0.9834$

$P(X>3417) =0.0166$

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0

3 years ago

list M and n are the zeros of the polynomial 3x square + 11 x minus 4 then find the value of m divided n plus n dividedm

Vaselesa [24]

Answer:

Step-by-step explanation:

3x²+11x-4

when splitting the middle term

it becomes

3x²+12x-1x-4

=3x(x+4)-1(x+4)

(3x-1)(x+4)

either 3x-1=0 then x=1/3

or x+4=0 then x= -4

m=1/3

n=-4

therefore

value of m divided n plus n dividedm=1.25

hope this helps plzz mar me brainliest

5 0

3 years ago