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2 years ago

Please help me with my work

Mathematics

1 answer:

Thepotemich [5.8K]2 years ago

6 0

Answer:

JM = 5 mm

Step-by-step explanation:

Δ JMK is the right angled triangle ⇒ JM² = JK² + KM²

JM² = 3² + 4²

JM = 5 mm

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Karen purchased a prepaid phone card for $30. Long distance calls cost 16 cents a minute using this card. Karen used her card on

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30-24.08=5.92, 5.92/.16=37 minutes

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3 years ago

Above are two different models of the same triangular handkerchief. If the area of the model on the right is 36 sq cm, what is t

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The answer is B 12 sq cm

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2 years ago

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Alexus [3.1K]

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3 years ago

Markin is making a flag shaped like a square. Each side measures 13 m. He wants to add ribbon along the edges. He has 48 m of ri

Marina86 [1]

Answer:

Ribbon can't be enough

Step-by-step explanation:

Markin is making a flag shaped like a square. Each side measures 13 m. He wants to add ribbon along the edges. He has 48 m of ribbon. Does he have enough ribbon? If it is not enough,how much more ribbon needed?

Given :

Side length of square shaped flag = 13 m

Length of ribbon markin has to add along edges = 48 m

To know if the ribbon will enough ; we obtain the perimeter of the square shaped flag ;

4 * side length

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3 years ago

What is the answer? x^2 + 4x - 6 = 0

vodka [1.7K]

First we have to find $\Delta$ from the equation $b^{2} -4ac$ where a, b and c are consecutive coefficients of the equation. In this case: $a=1, b=4, c=-6$

 $\Delta =4^2-4*(-6)=16+24=40$ , 

Later we will need to use $\sqrt{\Delta}$ sofor us $\sqrt{40}$ . It can be then simplified to $2 \sqrt{10}$ .

Then we use quadratic formula $x=\frac{-b\pm \sqrt{\Delta} }{2a}$ to see what are the options for x.

$x=\frac{-4\pm 2\sqrt{10}}{2}$
$x=- 2 \pm \sqrt{10}$

The answer for your question:
 $x=- 2 + \sqrt{10}$ or $x=- 2 - \sqrt{10}$

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4 years ago