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dezoksy [38]
3 years ago
6

PLEASE HELP! I WILL GIVE YOU BRAINLIEST!

Mathematics
2 answers:
avanturin [10]3 years ago
8 0

Answer:

27 45 33 52 29 40 96 47 40

Step-by-step explanation:

(can i please have braniest? :)

velikii [3]3 years ago
6 0

Answer: 27 45 33 52 29 40 96 47 40  

Step-by-step explanation:

Mean (Average) 45.444444444444

Median 40

Range 69

Mode 40, appeared 2 times

Geometric Mean 42.331583531044

Largest 96

Smallest 27

Sum 409

Count 9

Sorted Data Set: 27, 29, 33, 40, 40, 45, 47, 52, 96

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Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti
natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5

Simplifying:

f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

P(A) = \int_{5}^{15} = \frac{375}{t^4}

Integral of \frac{1}{t^4} = t^{-4} is \frac{t^{-3}}{-3} = -\frac{1}{3t^3}

Then

\int \frac{375}{t^4} dt = -\frac{125}{t^3}

Applying the limits, by the Fundamental Theorem of Calculus:

At t = 15, f(15) = -\frac{125}{15^3} = -\frac{1}{27}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

P(B) = \int_{5}^{10} = \frac{375}{t^4}

We already have the integral, so just apply the limits:

At t = 10, f(10) = -\frac{125}{10^3} = -\frac{1}{8}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0
3 years ago
OMG please help ASAP
Scorpion4ik [409]

Answer:

what do you need help on?

Step-by-step explanation:

4 0
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What's the answer to 2+4x19-5
fgiga [73]
Simple. 4x19 = 76+2 = 78-5 = 73
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The following table gives the mean scores for 4 different classes
aksik [14]

Answer:

a

Step-by-step explanation:

a

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2y+4x=12 in slope intercept form <br><br> 2x=y=-10 in slope intercept form
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Answer:

y = -2x +6

second equation is incorrect.

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Step-by-step explanation:

7 0
4 years ago
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