Answer:
C
Step-by-step explanation:
sqrt(a^7) = sqrt(a^6 * a)
Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
Answer:
The x-intercept is at the point (5,0).
Step-by-step explanation:
-2x + 5y = -10
At the x intercept y = 0 so we substitute y = 0 into the given equation:
-2x + 5(0) = -10
-2x = -10
x = 5.
Answer: 18 ≤ 6*S ≤ 30
Where S is the number of salmon fillets in one single package.
Step-by-step explanation:
Let's define S as the number of salmon fillets in one package.
We know that it contains at least 3, and no more than 5, then we can write:
3 ≤ S ≤ 5
Now we want to know the total number of salmon fillets that could be on 6 packages, then if S is the number of salmon fillets in one package, 6*S will e the number of salmon fillets in 6 packages.
We can find this by multiplying the inequality:
3 ≤ S ≤ 5
by 6.
We get:
6*3 ≤ 6*S ≤ 6*5
18 ≤ 6*S ≤ 30
Then in 6 packages, we could have any number between 18 and 30 fillets of salmon.
