<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u> </u>√15 units
Step-by-step explanation:
Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .
As we know ,
Distance(D) = √(x^1-x^2) +(y^1-y^2)
Now,
D= √(x^1-x^2) +(y^1-y^2)
= √(6-1) +(1+9)
= √5+10
= √15 units
: Therefore the distance between (6,1) and (1,-9) is √15 units.
Answer:
x=17
Step-by-step explanation:
This should be for a "kite": AD=DC, AB=BC and ∠A=∠C
8x-27 = 3x+58
5x = 85
x = 17
Answer:
m=2
Step-by-step explanation:
42=8m+13m
or,42=21m
or,42/21=m
or,m=2
This is the required answer for m.
To check,
42=8×2+13×2
42=16+26
42=42
Correct
Answer:
The degrees of freedom associated with the critical value is 25.
Step-by-step explanation:
The number of values in the final calculation of a statistic that are free to vary is referred to as the degrees of freedom. That is, it is the number of independent ways by which a dynamic system can move, without disrupting any constraint imposed on it.
The degrees of freedom for the t-distribution is obtained by substituting the values of n1 and n2 in the degrees of freedom formula.
Degrees of freedom, df = n1+n2−2
= 15+12−2=27−2=25
Therefore, the degrees of freedom associated with the critical value is 25.
Answer:
3(x - 10)
Step-by-step explanation:
3x - 30 = 3(x - 10)
