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3 years ago

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PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORECT QUESTION IS IN PICTUR

E BELOW (no links my computer is very slow and wont run some things)

1 answer:

allsm [11]3 years ago

8 0

The answer to that question is the third one

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What is the product of 8 times 4 minus the sum of 12 and 7?

klio [65]

Answer:

13

Step-by-step explanation:

8 × 4 = 32

12 + 7 = 19

32 - 19 =13

5 0

3 years ago

carmen recovered 2 gold bars that were stolen from a safe. the first bar weighed 2 2\5 pounds. the second bar weighed 1 2\3 time

TiliK225 [7]

What you do is 2 2/5 times 1 2/3
Change them to improper fractions will be:
12/5 Times 5/3

You will get:
60/15

That would make you :
4 pounds if you simplify it

She recovered 4 pounds of gold!

3 0

3 years ago

You purchase a total of 45 shares of stocks from 3 different companies. You purchase twice as many shares of company c stock as

bearhunter [10]

A)The total cost would be: x=15a+12b+18c where x is the total cost and a,b,and c are the amount of stocks you bought from their respective companies.

B) Since you bought 10 A stocks, you must have bought 20 C stocks. That adds up to 30 bought, leaving 15 for B.

x=(15)(10)+(12)(15)+(18)(20)
x=150+180+360=$690 spent

C) A's stock is now 15(1.25) which is 18.75. C's stock is now 18(.90) which is 16.2
new equation is 18.75a+12b+16.2c=x

D) Substitute the number of stocks we bought from each in again:
187.5+180+324=$691.5

The cost went up slightly, so divide 690/691.5 then multiply that number by one hundred. You get that you spent in B 99.8% the amount you spent in C. So 100-99.8= an increase of <u>.2% </u>

8 0

4 years ago

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

katrin [286]

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

Explanation:

let the amount of water = w

amount of water + amount of antifreeze will give 320 gallons of mixture

w + amount of antifreeze = 320

amount of antifreeze = 320 - w ...(1)

The concentration for the antifreeze = 80% = 0.8

The concentration of the mixture = 15% = 0.15

From our question, we are mixing antifreeze with pure water (two different things). In our calculation, we can write the concentration in terms of water or in terms of antifreeze.

Writing the concentration in terms of amount of antifreeze

0.8(amount of antifreeze) + percent of antifreeze (amount of water) = concentraton of the mixture

The mixture contains 15% antifreeze

water contains no antifreeze, percent = 0

0.8(320 - w) + 0(w) = 0.15(amount of mixture)

0.8(320 - w) + 0 = 0.15(320)

256 - 0.8w + 0 = 48

256 - 0.8w = 48

collect like terms:

256 - 48 = 0.8w

208 = 0.8w

divide both sides by 0.8:

208/0.8 = w

w = 260

substitute for w in equation (1)

amount of antifreeze = 320 - 260 = 60

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

3 0

1 year ago

Find the area of the curve y= f(x) = x between x = 5 and x = 10

Tems11 [23]

Answer:

the area of the curve y= f(x) = x between x = 5 and x = 10

$A=\frac{75}{2}$

Step-by-step explanation:

Finding the area of the curve y = f(x) = x between x = 5 and x = 10

Using the Area formula

$A=\int _a^b\:f\left(x\right)dx$

As the area of curve lies between x = 5 and x = 10

so

a = 5, b = 10

so the integral expression becomes

$A=\int _5^{10}xdx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5$

$=\left[\frac{x^2}{2}\right]^{10}_5$

$=\frac{1}{2}\left[10^2-5^2\right]$

$=\frac{1}{2}\cdot \:75$

$=\frac{75}{2}$

Therefore, area of the curve y= f(x) = x between x = 5 and x = 10

$A=\frac{75}{2}$

4 0

3 years ago