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Rufina [12.5K]
3 years ago
5

What are the solutions for x when y is equal to 0 in the quadratic function y= x2 + x - 72?

Mathematics
1 answer:
Ahat [919]3 years ago
3 0
0 = x^2 + x - 72
x^2 + x - 72 = 0
x^2 + 9x - 8x - 72 = 0
X (x + 9) - 8 (x + 9) = 0
(X + 9) (x - 8) = 0

X + 9 = 0
X = -9

X - 8 = 0
X = 8

X (-9,8)

Answer is Option D
x = -9 or x = 8
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First tangent line:

y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5

Second tangent line:

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Step-by-step explanation:

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