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3 years ago

Which expressions are equivalent to -90-60w?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

6 0

Therefore the answer is the first one

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2/5 divided 1/2 as a unit rate

Yanka [14]

Answer:

2/5 divided 1/2 as a unit rate .what do you mean

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4 years ago

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Which number line shows the estimate of 22 in the correct interval of integers?

Marta_Voda [28]

Answer:

the answer is B

Step-by-step explanation:

Just estimate ex: 5 x 5 would be 25, so sqrt 22 would be just before the 5.

5 0

3 years ago

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3 times the measure of an angle is 14 less than the measure of its complement. What is the measure of the angle? 19° 57° 71° 76°

liberstina [14]

Answer:

x = 19°

Step-by-step explanation:

Let The angle be "a"

Now according to the question,

⇒ 3 × a = (90° - a) - 14° (Then remove the brackets)

⇒ 3a = 90° - a - 14°

⇒ 3 + a = 76°

⇒ 40° = 76°

⇒ a = 76/4

Now since you got 76/4 you have to make it into simplest form so it'll be :

19/1

Your answer is : a = 19°

4 0

3 years ago

Please help with this one idk how to find slope lol

Harman [31]

Answer: 2/3

Step-by-step explanation: Rise/Run

8 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

4 0

4 years ago