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2 years ago

PLEASE HELPP!!!!!! FOR 10 POINTS. Am I right? Show work if I’m wrong

Mathematics

2 answers:

7nadin3 [17]2 years ago

6 0

Answer:

you are correct, they are supplementary

Step-by-step explanation:

Sholpan [36]2 years ago

3 0

Answer:

Yes! You are correct! The angles added together produce 180degrees, therefore, is supplementary. Just like the fellow above me said :)

Step-by-step explanation:

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Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

2 years ago

The train station clock runs too fast and gain 11 minutes every 3 days. How many minutes and seconds will it have gained at the

WARRIOR [948]

660sec in 3 days.
So 220sec per days
220•5= 1100
1100sec = 18min and 30 second.

Ans:
18min and 30 sec

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Answer:

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Step-by-step explanation:

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jonny [76]

Answer:

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Step-by-step explanation:

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Can someone please help iam new to this and I don't get anything I would be great if you do all of them but show work please.

Ymorist [56]

ANSWER(S):

(located in file)

EXPLANATION(S):

(located in file)

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