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drek231 [11]
3 years ago
15

describe how to transform (^5 square root x^7)^3 into an expression with a rational exponent. make sure you respond with complet

e sentences
Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

x^\frac{21}{5}

Step-by-step explanation:

We are given an expression and we have to transform it into an expression with exponent.

5th root of x can be written as x^\frac{1}{5}

(\sqrt[5]{x^7})^3\\\\((x^7)^\frac{1}{5} )^3


The powers outside will be multiplied as: (x^a)^b = x^{ab}

(x^\frac{7}{5} )^3\\x^\frac{7*3}{5}\\x^\frac{21}{5}


where the exponent is \frac{21}{5} and it is a rational number by definition of rational numbers

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Damaged items are marked down 25% to 40%. A newspaper coupon holder; to an additional 10% markdown of the new price due to the d
kobusy [5.1K]

Answer:

B. GHC 50.00

Step-by-step explanation:

The given parameters are;

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

We note that a markdown is the difference between the price an item is placed at for retail sale, and the actual price the item is sold

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40% as follows;

Price of item marked down due to damage, we remove 40% from the price to get;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

The markdown the coupon holder is to get = 10% of the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

Therefore;

The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown here;

brainly.com/question/20705786

5 0
2 years ago
Order the following numbers from least to greatest <br> -9/2<br> 0<br> 1 3/5<br> 9/7<br> 2/3
marysya [2.9K]

\frac{-9}{2}

0

\frac{2}{3}

\frac{9}{7}

1\frac{3}{5}

3 0
2 years ago
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Determine the domain and range of the graphed function
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Answer:

B

Step-by-step explanation:

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3 years ago
a ships triangular signal flag has a base of 8 inches and an area of 64 square inches.what is the height of the signal flag?
wel
Area of a triangle is 1/2b×h
a=1/2b×h
64=1/2 8×h
64= 4 × h
64÷4=16

Answer: the height is 16 inches

4 0
3 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
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