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drek231 [11]
3 years ago
15

describe how to transform (^5 square root x^7)^3 into an expression with a rational exponent. make sure you respond with complet

e sentences
Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

x^\frac{21}{5}

Step-by-step explanation:

We are given an expression and we have to transform it into an expression with exponent.

5th root of x can be written as x^\frac{1}{5}

(\sqrt[5]{x^7})^3\\\\((x^7)^\frac{1}{5} )^3


The powers outside will be multiplied as: (x^a)^b = x^{ab}

(x^\frac{7}{5} )^3\\x^\frac{7*3}{5}\\x^\frac{21}{5}


where the exponent is \frac{21}{5} and it is a rational number by definition of rational numbers

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Solve the system using the substituion method<br> -4x+y=8<br> x-3y=9
lions [1.4K]
Hi there!

x - 3y = 9
x = 9 + 3y
 
-4x + y = 8
-4(9+3y) + y = 8
-36 - 12y + y = 8
-36 - 11y = 8
-11y = 44
-y = 4
y = -4

x - 3y = 9
x - 3(-4) = 9
x + 12 = 9
x = 21

So, your answers are y = -4 and x = 21.

Hope this helps!
3 0
3 years ago
If r=20.5 and s=34.2 find S Round to the nearest tenth
astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

 \alpha =arctan(\frac{opposite}{adjacent})

Knowing that: you need to find the measure of the angle "S" , r=20.5 (which is the adjacent side) and s=34.2 (which is the opposite side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get that the measure of "S" rounded to the nearest tenth is:

S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°

7 0
3 years ago
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Gnesinka [82]

Answer:

The answer is Graph D.

Step-by-step explanation:

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2 years ago
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Evaluate if m equals 10 + n equals 12: n-m+2n÷12 can you please show me how you got this answer
Anna71 [15]
Plug in m=10 n=12
12 - 10 + 2(12) + 12 \\ 12 - 10 + 24 + 12 \\ 2 + 24 + 12 \\ 26 + 12 \\  = 38
7 0
3 years ago
A delivery of 5 large boxes and 3 small boxes has a total mass of 137 kilograms. A delivery of 2 large boxes and 6 small boxes h
lawyer [7]

Answer:

Large boxes are 18.25 kg

Small boxes are 15.25 kg

Step-by-step explanation:

This is a system of equations. You need to set up each equation first.

I am assigning x to be big boxes and y to be small boxes.

5x + 3y = 137

2x + 6y = 128

To solve, you will need to eliminate a variable. That means you will have to multiply one of the equations by a number to make it so a variable will be eliminated. I will be multiplying the top equation by -2.

-2 ( 5x + 3y = 137)

    2x + 6y = 128

Distribute the -2 to everything in the parentheses in the first equation.

-10x - 6y = -274

2x + 6y = 128

Notice the 6y will go away because -6y + 6y = 0. Now add the equations together. The remaining equation is:

-8x = -146

Solve for x by dividing by -8.

x = 18.25

Now plug that into one of the original equations.

2(18.25) + 6y = 128.

36.5 + 6y = 128                Subtract 36.5 from each side

-36.5            -36.5

6y = 91.5                          Divide by 6 to solve

y = 15.25

7 0
1 year ago
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