A value that "lies outside" (is much smaller or larger than)
Given function : 3x−6y=12.
We are given x : −2 0 4.
We need to find the values of y's for x=-2, x=0 and x=4.
Plugging x=-2 in the given equation, we get
3(-2)−6y=12
-6 - 6y = 12.
Adding 6 on both sides, we get
-6+6 - 6y = 12+6
-6y = 18.
Dividing by -6 on both sides, we get
y= -3.
On the same way, plugging x=0.
3(0)−6y=12
-6y =12.
y=-2.
Plugging x=4,
3(4)−6y=12
12 -6y = 12.
Subtracting 12 on both sides.
12-12 -6y = 12-12
-6y=0
y=0.
Therefore,
<h3>x −2 0 4</h3><h3>y -3 -2 0</h3>
Answer:
49,850.64
Step-by-step explanation:
To find the area of a circle, you must use the formula pi r ^2 (pi r squared).
In this case, we are using 3.14 for pi, so we can add that into the formula.
3.1r^2
We also know the radius, so we can add that in too.
3.14 x 126 ^2
Now solve.
126^2 = 15,876
15,876 x 3.14 = 49,850.64
49,850.64 is the answer.
Hope this helped!
Answer:
Step-by-step explanation:
Recall that a horizontal translation (shift) in 3 units to the right involves directly subtracting 3 from the variable x (horizontal axis variable) , and that moving the function up 5 units involves adding to the whole function 5 units. That is:
Answer:
She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2.
Step-by-step explanation:
i got my rerecord from my flash cards my teacher made of some answers
