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IceJOKER [234]
3 years ago
13

How do we do question 51? Lot of points!

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

Using a *2 -b*2 = (a-b) factor the expression. Factor out two from the expression. Reduce the fraction with x-3.

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HELP PLEASE I WILL GIVE BRAINLIEST
Andrei [34K]

Answer:

The slope intercept form is y = mx + b, where b is the y-intercept. In the equation y = 2x - 1, the y-intercept is -1. So, if you have an equation like y = 4x, there is no "b" term. Therefore, the y-intercept is zero, and the line passes through

4 0
2 years ago
Read 2 more answers
What is 24tenths÷8
Taya2010 [7]

Answer:

.03

Step-by-step explanation:

The answer would be .03 as you are dividing .24 by 8, which would be 3 if there was no decimal point. Though, .24 is two places past the ones place so the answer would have to be two places past the ones place. If you divide it, 8 can't go into 2, so you would put a 0 above it. Though, 8 can go into 24 three times, so you would put three. Therefore, your answer would be .03 as it is two places past the ones place and if it is multiplied by 8, it would make .24, or 24 tenths.

7 0
3 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
13. Distributive Property<br> 3(x - 1) = 3x - ?
goblinko [34]

Answer:

\huge\boxed{3x-3}

Step-by-step explanation:

3(x-1)=\\\\\text{Distribute: }\left \{ {{3*x=3x} \atop {3*-1=-3}} \right.\\\\3(x-1)=\boxed{3x-3}

8 0
3 years ago
Read 2 more answers
Factor completely. 12x4+18x3+45x2 Enter your answer in the box.
lukranit [14]

QUESTION 1

The given expression is

12x^4+18x^3+45x^2

The greatest common factor is 3x^2.

We factor to obtain;

3x^2(4x^2+6x+15)

QUESTION 2

The given quadratic equation is

x^2+6x-72=0

We split the middle term to obtain

x^2+12x-6x-72=0

Factor by grouping;

x(x+12)-6(x+12)=0

(x+12)(x-6)=0

Use zero product property;

(x+12)=0\:\:or\:\:(x-6)=0

x=-12\:\:or\:\:x=6

QUESTION 3

The given system of equation is

3x+4y=-8

7x-3y=6

If we multiply 3x+4y=-8 by 3, we obtain;

9x+12y=-24

If we multiply 7x-3y=6 by 4 we obtain;

28x-12y=24

Adding the last two equations will give us;

37x=0

The y-variable is eliminated.

Answer:Multiply 3x+4y=−8

by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.

6 0
3 years ago
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