1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Troyanec [42]
2 years ago
13

A recent article published in Berry Weekly reported a probability distribution for the different types of jelly that

Mathematics
1 answer:
Len [333]2 years ago
4 0

Answer:

Step-by-step explanation:

You might be interested in
If a insect is 0.095 long how long is it if looking through a microscope 100 times how long would the insect be
Sliva [168]

9.5.....................


5 0
3 years ago
Need help in number 12 and 13 PLEASEE!! I don’t get it and I start school the day after tomorrow
Natasha_Volkova [10]

Answer:

The explanations for the graphs are provided down below. Please let me know if you have any questions about my answer.

12 and 13 as written on the worksheet is right.

Step-by-step explanation:

12) The answer given is correct.

The relation between x and y is given as:

y=\frac{x^2}{2}-3 with x \in \{-4,-2,0,2}.

I replaced the word domain with x since the domain is the set of x's for which the relation exists.

We are going to replace x with each of the x's given to see what y corresponds to each.

Let's begin with x=-4.

y=\frac{x^2}{2}-3 with x=-4:

y=\frac{(-4)^2}{2}-3

y=\frac{16}{2}-3

y=8-3

y=5.

So (-4,5) is an ordered pair that should be on our graph.

To find this point you move left 4 from origin then up 5. Now you put a dot where you have landed. Your graph does show this point.

Moving on.

Let's do the next x: x=-2.

y=\frac{x^2}{2}-3 with x=-2:

y=\frac{(-2)^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (-2,-1) is an ordered pair that should be on our graph.

To find this point you move left 2 from origin and then down 1.  Now you put a dot where you have landed. Your graph shows this point as well.

Now x=0.

y=\frac{x^2}{2}-3 with x=0:

y=\frac{0^2}{2}-3

y=\frac{0}{2}-3

y=0-3

y=-3

So (0,-3) is an ordered pair that should be on our graph.

To find this point you move left and right none and down 3.  Now you put a dot where you have landed. Your graph shows this point.

Now the last point will be at x=2.

y=\frac{x^2}{2}-3 with x=2

y=\frac{2^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (2,-1) is an ordered pair that should be on our graph.

To find this point you move 2 units right from the origin and then down 1 unit. Now put a dot where you landed.  The graph shows this point as well.

13) The answer given is correct.

g(x)=|x| is the parent function and makes like a V shaped graph where it's vertex is at (0,0).

If we want to move this graph right 3 it becomes:

m(x)=|x-3| \text{ or } m(x)=|(-1)(-x+3)|=|-1||-x+3|=1|-x+3|=|-x+3|=|3-x|.

If you move that up once it becomes:

n(x)=|x-3|+1 or n(x)=|3-x|+1 which is the curve given.

If you don't know about transformations you can choose a few points to plug in to see what's going on with the graph.

Let's choose x=-5,-3,-1,0,1,3,5.

x=-5

f(-5)=|3--5|+1=|3+5|+1=|8|+1=8+1=9.

There is no room for (-5,9) on our graph but if you extended the left hand side of the absolute value function there you would see that (-5,9) is reached.

x=-3

f(-3)=|3--3|+1=|3+3|+1=|6|+1=6+1=7.

(-3,7) should be a point on the graph. Same thing for this point as (-5,9).

x=-1

f(-1)=|3--1|+1=|3+1|+1=|4|+1=4+1=5.

(-1,5) is located on the graph.

x=0

f(0)=|3-0|+1=|3|+1=3+1=4.

(0,4) is also located on the graph.

x=1

f(1)=|3-1|+1=|2|+1=2+1=3.

(1,3) is located on the graph.

x=3

f(3)=|3-3|+1=|0|+1=0+1=1.

(3,1) is located on the graph.

x=5

f(5)=|3-5|+1=|-2|+1=2+1=3.

(5,3) is located on the graph.

Now if we weren't given the graph already:

I would plot the points I found which were:

(-5,9)

(-3,7)

(-1,5)

(0,4)

(1,3)

(3,1)

(5,3)

We should get a basic idea of what the function looks like from these points.

I will graph them. You will have to connect these points because the domain isn't discrete like number 12 is.  That is they didn't list out elements for the domain.

I'm going to graph one more point after x=5.

How about x=7?

f(7)=|3-7|+1=|-4|+1=4+1=5

So (7,5) is also a point on the graph.

You should see that the blue points are following the red path I made there.

8 0
3 years ago
A professional football prospect runs 40 yards dash in 5 seconds. What is the player's average speed over this distance
Leto [7]

Answer:

average speed = 8y/s

Step-by-step explanation:

  • What is the player's average speed over this distance ?

Formula

s = d/t

d = 40 yards

t = 5 seconds

s = 40y/5s

= 8y/s

4 0
3 years ago
What is the solution for x in the given equation? sgrt9x+7+sgrt2x=7
aliya0001 [1]
X=2

Hope that helps!
(Please Mark as Brainliest!)
8 0
3 years ago
Find the smallest possible integer value of k for which 264k is a perfect square.
wolverine [178]

Step-by-step explanation:

264k

= 2³ * 3 * 11 * k

Hence, k = 2 * 3 * 11 = 66.

3 0
3 years ago
Read 2 more answers
Other questions:
  • Anybody know ? 9& 10
    15·1 answer
  • I need help I just got in trouble for not finishing this class in time and now I’ve been stuck on the same section for weeks I h
    6·1 answer
  • In June, a runner ran a mile in 7:45. In September, the runner ran a mile in 5:51. what is the percent of change
    9·1 answer
  • Help with these math problems to get 40 points
    14·2 answers
  • Estimate the perimeter of the figure to the nearest whole number.
    5·1 answer
  • The length of a rectangle is the sum of the width and 2. The area of the rectangle is 48 units. What is the length, in units, of
    5·1 answer
  • How do i simplify this
    12·1 answer
  • How do you write 9/100 as a decimal?<br> 0.09<br> 9.0<br> 0.9
    8·2 answers
  • What is 2+2-4/5-9+98
    5·2 answers
  • Carl is deriving the quadratic equation by completing the square. His work at one of the steps is shown. x + b/na = + or - b^2-4
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!