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murzikaleks [220]

3 years ago

7

If the area is 64 inches squared, what is the missing length ?

2 answers:

OleMash [197]3 years ago

6 0

The area of a parallelogram is length × width.

Since you already know the area of the parallelogram, make an equation where you have the width but not the height, and length × width = 64 in².

The width of the parallelogram is shown on the diagram = 8 inches. You are missing the length = x. Your equation will look like:

x × 8 = 64, or 8x = 64. Solve for x to find the length of the parallelogram.

8x = 64
Divide both sides by 8 to isolate x.

x = 8
The missing length is 8 inches.

Igoryamba3 years ago

3 0

The area of a parallelogram is equal to the base multiplied by the height. Since we can see that this is a parallelogram (because of the two pairs of parallel sides), we now know how to find the area. Since we already know the height and the area, we can substitute their values into the formula to solve for the base.

8 * (the base) = 64

Divide each side by 8 to figure out the length of the base

the base = 8 in.

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The base of a rectangle lies on the x-axis, while the upper two vertices lie on the parabola y = 13 − x2. Suppose that the coord

Misha Larkins [42]

Answer:

Area of Rectangle = $26x - 2x^3$

Step-by-step explanation:

Rectangle two vertices lie on x axis ; two vertices lie on parabola $y = 13 - x^2$ .

Supposing coordinates of upper right vertex of rectangle are P = $x , y$

Due to parabola symmetry, width of rectangle is twice the distance horizontal (X) axis distance between Y axis & point P.

Width of rectangle = $2x$

Length of rectangle = $y$ ; $y = 13 - x^2$

Area of Rectangle = Length x Width

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3 years ago

What is 22/40 in simplest form

OLga [1]

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7 0

3 years ago

Read 2 more answers

A student scored 75 and 97 on her first two quizzes. Write and solve a compound inequality to find the possible values for a thi

Rainbow [258]

Answer:

$85 \le \frac{75 + 97 + n}{3} \le 90$ ; $83 \le n \le 98$

Step-by-step explanation:

Score of the first two quizzes: 75 and 97

Let n represent the third score

Average score would be: $\frac{75 + 97 + n}{3}$ .

Given that the average score fall between 85 and 90, this can be represented by the compound inequality as shown below:

$85 \le \frac{75 + 97 + n}{3} \le 90$

Solve for n in each statement that makes up the compound inequality:

$85 \le \frac{75 + 97 + n}{3}$

$85 \le \frac{172 + n}{3}$

Multiply both sides by 3

$85*3 \le 172 + n$

$255 \le 172 + n$

Subtract 172 from each side of the inequality

$255 - 172 \le n$

$83 \le n$

Also,

$\frac{75 + 97 + n}{3} \le 90$

$\frac{172 + n}{3} \le 90$

Multiply both sides by 3

$172 + n \le 90*3$

$172 + n \le 270$

Subtract 172 from both sides of the inequality

$n \le 270 - 172$

$n \le 98$

Combining both together, the possible values of her third quiz score would be:

$83 \le n \le 98$

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