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3 years ago

If the area is 64 inches squared, what is the missing length ?

Mathematics

2 answers:

OleMash [197]3 years ago

6 0

The area of a parallelogram is length × width.

Since you already know the area of the parallelogram, make an equation where you have the width but not the height, and length × width = 64 in².

The width of the parallelogram is shown on the diagram = 8 inches. You are missing the length = x. Your equation will look like:

x × 8 = 64, or 8x = 64. Solve for x to find the length of the parallelogram.

8x = 64
Divide both sides by 8 to isolate x.

x = 8
The missing length is 8 inches.

Igoryamba3 years ago

3 0

The area of a parallelogram is equal to the base multiplied by the height. Since we can see that this is a parallelogram (because of the two pairs of parallel sides), we now know how to find the area. Since we already know the height and the area, we can substitute their values into the formula to solve for the base.

8 * (the base) = 64

Divide each side by 8 to figure out the length of the base

the base = 8 in.

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3 years ago

M∠Q = <br> m∠R = <br> m∠S = <br><br> 40 POINTS!!!!!!!

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9514 1404 393

Answer:

∠Q = 89°

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Step-by-step explanation:

It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.

arc QRS = 2·∠P = 114°

So, ...

arc QR = arc QRS - arc RS = 114° -41° = 73°

The total of the arcs around the circle is 360°, so ...

arc PQ = 360° -arc PS -arc QRS

arc PQ = 360° -137° -114° = 109°

∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)

∠Q = 89°

∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)

∠R = 123°

∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)

∠S = 91°

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